Answer;
The correct answer would be Rr.
In a monohybrid cross, the phenotype ratio of 3:1 is obtained only when both the parents are heterozygous for the trait.
In this condition, the heterozygous genotype would be Rr. The phenotype of both the parents would be round seeds (R) as the round is a dominant trait.
The cross of these parents would produce offspring with three types of genotypes RR, Rr, and rr in ratio 1:2:1.
Thus, the phenotypic ratio would come out to be 3 (round seed):1 (wrinkled seed).
Answer:chemical reaction
Explanation:Enzymes are biological molecules (typically proteins) that significantly speed up the rate of virtually all of the chemical reactions that take place within cells. They are vital for life and serve a wide range of important functions in the body, such as aiding in digestion and metabolism.
Answer:
Explanation:
This question is a practical question and would require some sort of experiment. However, let's define what rate of reaction means. The rate of a chemical reaction (in this case fermentation) can be described as the speed at which the reaction occurs; meaning the speed at which product is formed per unit time.
The "claim" in the attachment in the question can be referred to as hypothesis since this question is an experiment. The null hypothesis here will be "<u>the rate of alcoholic fermentation is not affected by the type of sugar used as an energy source</u>".
The "evidence" from the attachment will be result of the experiment conducted which cannot be provided here.
However, the conclusion of this experiment (which also answers the main question; does the rate of alcoholic fermentation differ when different types of sugar are used as a source of energy?) should show that the rate of alcoholic fermentation should differ based on the type of sugar used. This is because different enzymes are responsible for the conversion of this disaccharide to the glucose monosaccharide which is what finally undergoes alcoholic fermentation. For example sucrose is broken down into glucose and fructose by sucrase while lactose is broken down into glucose and galactose by the enzyme lactase.
Note that the reaction rate from glucose to produce CO₂ (a product of fermentation) will be the same (regardless of source) but the reaction time from the disaccharide to glucose will be different because of the difference in enzyme and can also be determined by comparing the time to produce the CO₂ by the sugars and the time to produce same amount of CO₂ when given water in the experiment .
NN, ss, mm because homo means the same so if they are the same they are homozygous.
