As the cell size increases, the ratio of surface area to volume DECREASES.
The surface area to volume ratio refers to the area per unit volume of a cell. As a cell increase in size, the surface area and the volume of the cell also increase but at an unequal rate, a point will be reached where the ratio of the surface area to volume will be so low that the diffusion becomes very inefficient, at this point, the cell has to divide in order to increase its surface area to volume ratio and to increase its diffusion rate.
The balanced equation is
<span>8SO2 + 16H2S ----> 3S8 + 16H2O
</span>so
77g SO2 / 64g/mole = 1.203moles of SO2
<span>77g H2S / 34g/mole = 2.26moles of H2S
</span>now
<span>1.203 moles SO2 yields 3/8x amount that is = 0.456moles of S8
</span>so
<span>2.06moles H2S yields 3/16x amount = 0.386moles of S8
</span>hence
H2S = produce only 0.386moles of S8 = 98.98g S8
hope it helps
Answer and Explanation:
No thx, I have to study for my biology EOC exam..
