suppose you have the monohybrid pea plants in your garden and find that they produce round seed to wrinkled seeds in the ration
3:1. If the allele are designated (R & r) respectively, what is the probably genotypes of the rounds seeds with were produced?
1 answer:
Answer;
The correct answer would be Rr.
In a monohybrid cross, the phenotype ratio of 3:1 is obtained only when both the parents are heterozygous for the trait.
In this condition, the heterozygous genotype would be Rr. The phenotype of both the parents would be round seeds (R) as the round is a dominant trait.
The cross of these parents would produce offspring with three types of genotypes RR, Rr, and rr in ratio 1:2:1.
Thus, the phenotypic ratio would come out to be 3 (round seed):1 (wrinkled seed).
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Question is incomplete i have added full question in ask for detail section as well as in picture format with answer. See figure for clear explanation.
Answer:
(Twisted leaves)
The mutant allele is dominant to its corresponding wild-type allele
(Forked leaves)
The mutant allele is dominant to its corresponding wild-type allele
(pale leaves)
The mutant allele is neither dominant nor completely recessive to its corresponding wild-type allele
Explanation:
I have attached picture which explains phenomenon it self.
