Answer:
2522g
Explanation:
8Fe + S8 —> 8FeS
From the question,
8moles of Fe required 1mole of S8.
Therefore, Xmol of Fe will require 5.65mol of S8 i.e
Xmol of Fe = 8 x 5.65 = 45.2moles
Now we need to covert 45.2moles to gram. This is illustrated below below:
Molar Mass of Fe = 55.8g/mol
Number of mole of Fe = 45.2moles
Mass of Fe =?
Mass = number of mole x molar Mass
Mass of Fe = 45.2 x 55.8
Mass of Fe = 2522g
Therefore, 2522g of Fe is needed for the reaction.
Answer:
0.35 M
Explanation:
Molar mass of calcium chloride= 40+2(35.5)= 111gmol-1
Mass calcium chloride= 21.84g
Volume of solution= 562.43ml
From
n= CV
But n=m/M
n= number of moles
C=concentration
V= volume of solution in litres
m=mass of substance
M= molar mass of substance
n=21.84/111= 0.197moles
C= 0.197 ×1000/562.43
C= 0.35 M
A because magma is underground