Answer:
x=0
Step-by-step explanation:
I must assume that your goal is to "solve for x." State your goal explicitly each time you post a problem.
Combining like terms, we get 4x = 0, so that x = 0.
Check: Is 5(0) - 13 = 0 - 13 true? YES
The first 4 in the front has the relationship of the Thousands, and the 4 after that has a relationship of hundreds.
54/60 108/120 216/240 double both numbers each time
For Scott
- He is at 100km 30 degrees
For Spock
- He is at 110km 62 degrees
So The difference between them is just algebraic subtraction of their positions
- 110km 62°-100km 30°
- (110-100)km (62-30)°
- 10km 32° apart
Answer:
(f+g)(x)=5x²-4x+3
(f-g)(x)=3x²-2x+3
(fg)(x)

Step-by-step explanation:
Given that,
f(x)=4x²-3x
g(x)=x²-x+3
(f+g)(x)
=f(x)+g(x)
=4x²-3x+x²-x+3
=(4x²+x²)+(-3x-x)+3 [ combined the like terms]
=5x²-4x+3
(f-g)(x)
=f(x)-g(x)
=4x²-3x-(x²-x+3)
=4x²-3x-x²+x-3
=(4x²-x²)+(-3x+x)-3 [ combined the like terms]
=3x²-2x+3
(fg)(x)
=f(x).g(x)
=(4x²-3x).(x²-x+3)
=4x²(x²-x+3)-3x(x²-x+3)





