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vazorg [7]
3 years ago
14

Can someone please help me am stuck on this, thanks.

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

First box: -5, 0, 6, 9

Second box: 10, 12.5

Step-by-step explanation:

4x-12≤24

4x≤24+12

4x≤36

x≤36÷4

x≤9

So the first box would have all the solutions less than or equal to 9:

-5, 0, 6, 9

And the second box would have the solutions greater than 9:

10, 12.5

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The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviat
aleksley [76]

Answer:

4.5 hour and 2 hour

Step-by-step explanation:

Given: The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours.

To Find: If each time was increased by one hour, what would be the new mean and standard deviation.

Solution:

let the total numbers entries of hours in survey be   =   \text{N}

each entry in survey be  =  \text{x}_{i}

mean of survey is     =     \mu  =3.5 \text{hours}

standard deviation is  =   \sigma = 2 \text{hours}

if each entry in survey is increased by one hour then,

each new entry in survey  is =  \text{x}_{i}+1

the new mean is\mu_{new}  = \frac{\text{sum of all hours}}{total number of entries}

                                                \frac{\text{x}_{1} +1+\text{x}_{2}+1 +....+\text{x}_{N}+1 }{N}

                                                \frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})+\text{N}\times1 }{N}

                                                \frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})}{N}+\frac{\text{N}\times1 }{N}

                                             \mu_{new} = \mu + 1=4.5 \text{hours}

now,

standard deviation is      \sigma_{new}= \sqrt{\sum_{1}^{N}\frac{(\text{x}_{inew}-\mu_{new})^{2}}{N}}

                                   \text{x}_{inew}= \text{x}_{i}+1

                                   \mu_{new}=\mu+1        

putting values,

                                                \sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}+1-\mu-1)^{2}}{N}}

                                                \sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}-\mu)^{2}}{N}}= \sigma

                                 \sigma_{new}        =2

new mean and standard deviation are 4.5 and 2 \text{hours}

                                               

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3 years ago
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4 years ago
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Answer:

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