I. 3*2^0
II. 3*2^1
III 3*2^2
IV. 3*2^3
V. 3*2^4
VI. 3*2^5
The sum 3*(2^0+2^1+2^2+2^3+2^4+2^5)=3*(2^6-1)=3*(64-1)=3*63=189
D is the answer
Given:
Cost of printing a catalog: flat rate of $52 and $0.20 per copy.
C = 52 + 0.20x
C is the total cost of printing x number of copies.
x = 500
C = 52 + 0.20(500) = 52 + 100 = 152
x = 1000
C = 52 + 0.20(1000) = 52 + 200 = 252
x = 1500
C = 52 + 0.20(1500) = 52 + 300 = 352
x = 2000
C = 52 + 0.20(2000) = 52 + 400 = 452
x = 2500
C = 52 + 0.20(2500) = 52 + 500 = 552
Answer:
Put the equation in standard form by bringing the 4x + 1 to the left side.
7x2 - 4x - 1 = 0
We use the discriminant to determine the nature of the roots of a quadratic equation. The discriminant is the expression underneath the radical in the quadratic formula: b2 - 4ac.
b2 - 4ac In this case, a = 7, b = -4, and c = -1
(-4)2 - 4(7)(-1)
16 + 28 = 44
Now here are the rules for determining the nature of the roots:
(1) If the discriminant = 0, then there is one real root (this omits the ± from the quadratic formula, leaving only one possible solution)
(2) If the discriminant > 0, then there are two real roots (this keeps the ±, giving you two solutions)
(3) If the discriminant < 0, then there are two imaginary roots (this means there is a negative under the radical, making the solutions imaginary)
44 > 0, so there are two real roots
it is 3 numbers all together and they are 25, 36 and 49.
Answer:
D. 78°
Step-by-step explanation:
50°+28°= 78°
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