Answer:
3460
Step-by-step explanation:
Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2
now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5
thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"
5a+b = 5(6)+3 =3
10-r+5 = 10-(9)+5 =6
In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
2/sqrt 5
by rationalising the denominator,
2/sqrt 5 × sqrt 5/sqrt 5
= 2(sqrt 5)/sqrt 5(sqrt 5)
= 2 sqrt 5/5
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hope this helps! :))))
