From ideal gas equation that is pv =nRt
n=number of moles which can be written as the ratio between the weight of a gas that is mass and its molecular mass n=m/Mm
pv=(m/Mm)RT
density is=mass per unit volume
P=m/v by arranging the equation we get
R =0.082atm/mol/k
Mm=pRT/P=[(1.10 x10^-6 x1000g/l) xo.082 atm/mol/k x(80+273] /(1.00 x10^-3) =31.84 to the nearest ten is 32
hence the gas is oxygen
Answer:
0.2402 M
Explanation:
0.945 L sol contains = 0.227 moles
1 L sol will contain = (0.227/0.945)*1 = 0.2402 moles
Molarity = 0.2402 moles/L or M
<u>Answer:</u> The molarity of sulfuric acid is 0.0946 M
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is LiOH
We are given:
Putting values in above equation, we get:
Hence, the molarity of sulfuric acid is 0.0946 M
On the way to the lungs, air passes through the trachea.
hope this helps =)
1. Nucleic
2. Protein
3. Carbohydrates
4. Lipids