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3 years ago

Which of the following is a proton donor. a. Bronsted-Lowry Base 6 Bronsted-Lowry Acid c. Lewis Acid d. Lewis Base

Chemistry

1 answer:

Margarita [4]3 years ago

3 0

Answer:

Bronsted-Lowry acid

Explanation:

Bronsted-Lowry Base -

According to Bronsted-Lowry theory of acids and bases:

Acids are those substances which donate proton in the solution whereas bases are those substances which accept proton in the solution.

Consider an example,

$HCO_3^{-} + HOH\; \rightarrow H_2CO_3 + OH^{-}\\$

HCO3- behave as base as it accepts proton in the reaction whereas HOH behaves as acid as it releases proton.

According to Lewis theory of acids and bases:

Acids are electron acceptor and bases are electron donar. Acids are generally electron deficient species whereas Lewis are chemical species having lone pair of electrons.

For example, AlCl3 is behave as Lewis acid because of being electron deficient species.

NH3 is a Lewis base because of presence of lone pair of electrons.

Therefore, among given options, Bronsted-Lowry acid is the correct option.

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An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of

Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the alloy is 2.324 J/g°C

3 0

3 years ago

Calculate the number of molecules in 210 grams of H2O

spin [16.1K]

H2O=18.01g/mole. 210g divided by 18.01g/mole=11.653mole. 1 mole has 6.22x10^23 molecules. So there is 11.653x(6.22x10^23) molecules. Just multiply 11.653 by 6.22. Then put it as answerx10^23 molecules

4 0

3 years ago

Which set of properties distinguishes potential energy from kinetic energy?

fenix001 [56]

Kinetic energy is energy possessed by a body by virtue of its movement.

Potential energy is the energy possessed by a body by virtue of its position or state.

3 0

3 years ago

Convert the density of water, 1.00 g/mL to lb/ft3. Provide only the numerical value in your answer with the correct number of si

PtichkaEL [24]

Answer:

The density of water $1.00 g/ml=62.43 lbs/ft^3$ .