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2 years ago

15

How many protons, electrons, and neutrons does an atom with atomic number 50 and a mass number of 125 contain?

1 answer:

EleoNora [17]2 years ago

3 0

Answer:

a) 50 protons, 50 electrons, 75 neutrons

Explanation:

How many protons, electrons, and neutrons does an atom with atomic number 50 and a mass number of 125 contain?

a) 50 protons, 50 electrons, 75 trons

b) 75 electrons, 50 protons, 50 neutrons

c) 120 neutrons, 50 protons, 75 electrons

atomic number IS the number of protons

atomic mass IS the total of protons + neutrons

so 50 protons

125-50 = 75 neutrons

in a neutral atom,

number of negative electrons = number of positive protons

a) 50 protons, 50 electrons, 75 neutrons

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When copper is changed to copper(II) nitrate by the nitric acid, it is an example of a(n) ______-_______ reaction. (two words, i

Nataly_w [17]

Answer:

oxidation- reduction

Explanation:

where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent

<h2>Oxidize: copper = Cu+2</h2>

5 0

3 years ago

determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth m

mamaluj [8]

This is an incomplete question, here is a complete question.

Determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices.

(a) $1s^22s^22p^63s^23p^5$

(b) $1s^22s^22p^63s^23p^63d^74s^2$

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$

(d) $1s^22s^22p^63s^23p^63d^4s^1$

Answer :

(a) $1s^22s^22p^63s^23p^5$ → Halogen

(b) $1s^22s^22p^63s^23p^63d^74s^2$ → Transition metal

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$ → Transition metal

(d) $1s^22s^22p^63s^23p^63d^4s^1$ → Transition metal

Explanation :

Inert gas : These are the gases which lie in group 18.

Their general electronic configuration is: $ns^2np^6$ where n is the outermost shell.

Halogen : These are the elements which lie in group 17.

Their general electronic configuration is: $ns^2np^5$ where n is the outermost shell.

An alkali metal : These are the elements which lie in group 1.

Their general electronic configuration is: $ns^1$ where n is the outermost shell.

An alkaline earth metal : These are the elements which lie in group 2.

Their general electronic configuration is: $ns^2$ where n is the outermost shell.

Transition elements : They are the elements which lie between 's' and 'p' block elements. These are the elements which lie in group 3 to 12. The valence electrons of these elements enter d-orbital.

Their general electronic configuration is: $(n-1)d^{1-10}ns^{0-2}$ where n is the outermost shell.

(a) $1s^22s^22p^63s^23p^5$

The element having this electronic configuration belongs to the halogen family.

(b) $1s^22s^22p^63s^23p^63d^74s^2$

The element having this electronic configuration belongs to the transition family.

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$

The element having this electronic configuration belongs to the transition family.

(d) $1s^22s^22p^63s^23p^63d^4s^1$

The element having this electronic configuration belongs to the transition family.

4 0

3 years ago

1. To form a solution, ________.

adoni [48]

1.one substance must dissolve another : the solvent breaks the the solute causing it to dissociate into the solvent it can be both solids or gases that dissolve in the solute

2.the melting point will be higher than 100 degrees as the salt causes the solution to gain a higher melting point

3.either released or absorbed : energy is required to dissolve the solute but the solute may also release energy

4.the salt dissolved most quickly in the warm water : as there is more energy for the solute to dissolve

hope that helps

3 0

3 years ago

Read 2 more answers

On what day the lining of the uterus builds up

Mariulka [41]

28 days 3 2 2 2 3 3 3 do not mind these answers

7 0

4 years ago

Read 2 more answers

Five calcite, CaCO3 (MM 100.085 g/mol), samples of equal mass have a total mass of 12.2±0.1 g . What is the average mass and abs

Westkost [7]

Answer:

<em>The average mass of calcium in each sample is: </em><u>0.978 g</u>

<em />

<em>The absolute uncertainty is: </em><u>0.008 g</u>

Explanation:

The <em>absolute uncertainty </em>of the total samples indicated in the statement is ± 0.1 g.

When you multiply or divide quantities with uncertainties, you calculate the final uncertanty by adding the <em>relative uncertainties</em> together.

The relative uncertainty is the absolute uncertainty divided by the quantity:

Relative uncertainty = 0.1g / 12.2 g = 0.008

The average mass of calcium is calculated using proportions, along with the molar masses:

Molar mass of calcium: 40.078 g/ mol (from a periodic table)

Molar mass of calcite: 100.085 g/mol (given)

Proportion:

40.078 g of calcium / 100.085 g of calcite = x / 12.2 g of calcite

x = 12.2 × 40.078 / 100.085 g = 4.89 g calcium

So the total mass of calcium in the five samples is 4.89 g, and the average mass in each sample is:

Average mass = total mass of five samples / number of samples

Average mass = 4.89 g / 5 = <u>0.978 g of calcium</u>

So, the first answer is that the average mass of calcium in each sample is 0.978 g ( keep 3 signficant figures, such as the quntitiy 12.2 shows, as you have only used multiplication and division).

The absolute uncertainty of each sample is the relative uncertainty multiplied by the average mass of calcium of the five samples, rounded to one decimal:

Absolute uncertainty = 0.978 g × 0.008 ≈ 0.008 g

The answer to the secon question is that the absolute uncertaingy of calcium in each sample is 0.008 g.

7 0

4 years ago