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3 years ago

For an experiment, you place 15 g of ice with a temperature of -10 C into a cup and label

2 answers:

6 0

The correct answer is c. Temperature is the average kinetic energy of a sample so if two samples have the same temperature they will also have the same average kinetic energy. I hope this helps. Let me know if anything is unclear.

Darina [25.2K]3 years ago

5 0

Average kinetic energy is given by the formula:

KE(average) = 3/2*k*T

where k = Boltzmann constant = 1.38*10⁻²³ J/K

T = temperature in Kelvin (K)

Thus, the average KE is dependent only on temperature and independent of mass.

Since the temp in Cup A and B remains the same, the average KE will also be the same.

Ans C)

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ch question carries 2 mark. Time Remaining : 00 : 46 : 33 Some oxides are given below. (i)Na2O (ii)NO2 (iii) CO2 (iv) MgO a) Whi

cluponka [151]

<h3>Further explanation</h3>

The basic oxide is an oxide-forming a base solution.

These oxides are mainly from group 1 alkaline and group 2-alkaline earth

If this oxide is dissolved in water it will form an alkaline solution

LO + H₂O --> L(OH)₂ ---> alkaline earth

L₂O + H₂O --> LOH --> alkaline

So the basic oxides : Na₂O and MgO

Na₂O + H₂O --> NaOH (sodium hydroxide, strong base)

MgO + H₂O --> Mg(OH)₂ (magnesium hydroxide, strong base)

The aqueous solution of CO₂ , obtained by dissolving CO₂ in water

CO₂ + H₂O --> H₂CO₃ (carbonic acid)

In general, basic oxide is obtained from metal oxide, while acid oxide is obtained from non-metal oxide

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3 years ago

58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,

erica [24]

Answer and Explanation:

$Greetings!$

$Let's~answer~your~question!$

$Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.$

$\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}$

For % of N2 gas: 

 $100\% - (5\% + 12\%) = 83\% ~N2$ 

 $PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm$ 

 $PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm$ 

 $~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm$ 

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Answer:

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2 years ago