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Lyrx [107]
2 years ago
5

PLS HELP WILL MARK BRAINLIEST!

Mathematics
2 answers:
vlada-n [284]2 years ago
8 0

Answer:

5x-4y+13 (c)

Step-by-step explanation:

9-(4y-3x)+(2x+4)

9-4y+3x+2x+4

3x+2x-4y+9+4

5x-4y+13

elena-s [515]2 years ago
7 0

More than means addition.

C is the correct option.

= (2x + 4) + 9 - 4y + 3x

= 2x + 4 + 9 - 4y + 3x

= 5x + 13 - 4y

= 5x - 4y + 13

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Andrei [34K]
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For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37
Lyrx [107]

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

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4 0
3 years ago
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Elanso [62]

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: y=b^x

Our equation: y=6^x

Add alterations:

  1. Reflections = N/A
  2. Vertical & horizontal shifts = down 4
  3. Vertical & horizontal stretches = left approx 0.612

Final equation: y=6^x+0.612 - 4


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2 years ago
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bekas [8.4K]

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3 years ago
Which radical expression in the picture is equivalent to t^5/8?
mixas84 [53]
<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3

or in this case,

\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5

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