The percentage of the orignal uranium that remains after two half-lives is 25%
<h3>Data obtained from the question </h3>
- Original amount (N₀) = 100%
- Number of half lives (n) = 2
- Percentage remainig (N) =?
<h3>How to determine the percentage remaining</h3>
N = N₀ / 2ⁿ
N = 100 / 2²
N = 100 / 4
N = 25%
Thus 25% of the original sample remains
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