C2H6 is a chemical compound
Solution :
For the reaction :

we have
![$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$](https://tex.z-dn.net/?f=%24Ka%20%3D%20%5Cfrac%7B%5B%5Ctext%7BTris%7D%5E-%20%5Ctimes%20H_3O%5D%7D%7B%5Ctext%7BTris%7D%5E%2B%7D%24)


Clearing
, we have 
So to reach
, one must have the
concentration of the :
![$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$](https://tex.z-dn.net/?f=%24%5Ctext%7B%5BOH%7D%5E-%5D%3D10%5E%7B-pOH%7D%20%3D%206.31%20%5Ctimes%2010%5E%7B-7%7D%20%5Ctext%7B%20moles%20of%20base%7D%24)
So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.


Volume NaOH 
Tris mass 
Now to prepare the said solution we must mix:
gauge to 1000 mL with water.
B) They worries people would destroy the animals and land.
<span>The elements on the Periodic Table are arranged in order of increasing "Atomic number"
In short, Your Answer would be Option B
Hope this helps!</span>
Since the direction of particle displacement in electromagnetic waves is also perpendicular to the direction of motion, generating the waveform of visible light and other forms of electromagnetic radiation, they are also transverse waves.
In a transverse wave, the displacement is perpendicular to the direction of motion (at an angle of 90 degrees Celsius). The direction of displacement (up and down) in the case of the ocean wave is perpendicular to the direction of wave motion (horizontally along the water), making it a transverse wave.
How far a particle has moved from its original starting position, or, in the case of an ocean wave, how high or low the water is, is measured by its displacement or amplitude.
learn more about displacement here;
brainly.com/question/321442
#SPJ4