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2 years ago

Elemnt name, atomic number, atomic mass, protons, neutrons, elsctrons 1-10

1 answer:

4 0

<h2><em>Answer:</em></h2><h2><em>Hydrogen </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 1 </em></h2><h2><em> </em></h2><h2><em>Symbol: H </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 1 </em></h2><h2><em> </em></h2><h2><em>Protons: 1 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 0 </em></h2><h2><em> </em></h2><h2><em>Electrons: 1 </em></h2><h2><em> </em></h2><h2><em>Helium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 2 </em></h2><h2><em> </em></h2><h2><em>Symbol: He </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 4 </em></h2><h2><em> </em></h2><h2><em>Protons: 2 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 2 </em></h2><h2><em> </em></h2><h2><em>Electrons: 2 </em></h2><h2><em> </em></h2><h2><em>Lithium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 3 </em></h2><h2><em> </em></h2><h2><em>Symbol: Li </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 7 </em></h2><h2><em> </em></h2><h2><em>Protons: 3 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 4 </em></h2><h2><em> </em></h2><h2><em>Electrons: 3 </em></h2><h2><em> </em></h2><h2><em>Beryllium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 4 </em></h2><h2><em> </em></h2><h2><em>Symbol: Be </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 9 </em></h2><h2><em> </em></h2><h2><em>Protons: 4 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 5 </em></h2><h2><em> </em></h2><h2><em>Electrons: 4 </em></h2><h2><em> </em></h2><h2><em>Boron </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 5 </em></h2><h2><em> </em></h2><h2><em>Symbol: B </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 11 </em></h2><h2><em> </em></h2><h2><em>Protons: 5 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 6 </em></h2><h2><em> </em></h2><h2><em>Electrons: 5 </em></h2><h2><em> </em></h2><h2><em>Carbon </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 6 </em></h2><h2><em> </em></h2><h2><em>Symbol: C </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 12 </em></h2><h2><em> </em></h2><h2><em>Protons: 6 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 6 </em></h2><h2><em> </em></h2><h2><em>Electrons: 6 </em></h2><h2><em> </em></h2><h2><em>Nitrogen </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 7 </em></h2><h2><em> </em></h2><h2><em>Symbol: N </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 14 </em></h2><h2><em> </em></h2><h2><em>Protons: 7 </em></h2><h2><em> </em></h2><h2><em>Neutrons:7 </em></h2><h2><em> </em></h2><h2><em>Electrons: 7 </em></h2><h2><em> </em></h2><h2><em>Oxygen </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 8 </em></h2><h2><em> </em></h2><h2><em>Symbol: O </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 16 </em></h2><h2><em> </em></h2><h2><em>Protons: 8 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 8 </em></h2><h2><em> </em></h2><h2><em>Electrons: 8 </em></h2><h2><em> </em></h2><h2><em>Fluorine </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 9 </em></h2><h2><em> </em></h2><h2><em>Symbol: F </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 19 </em></h2><h2><em> </em></h2><h2><em>Protons: 9 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 10 </em></h2><h2><em> </em></h2><h2><em>Electrons: 9 </em></h2><h2><em> </em></h2><h2><em>Neon </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 10 </em></h2><h2><em> </em></h2><h2><em>Symbol: Ne </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 20 </em></h2><h2><em> </em></h2><h2><em>Protons: 10 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 10 </em></h2><h2><em> </em></h2><h2><em>Electrons: 10 </em></h2><h2><em> </em></h2><h2><em>Sodium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 11 </em></h2><h2><em> </em></h2><h2><em>Symbol: Na </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 23 </em></h2><h2><em> </em></h2><h2><em>Protons: 11 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 12 </em></h2><h2><em> </em></h2><h2><em>Electrons: 11 </em></h2><h2><em> </em></h2><h2><em>Magnesium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 12 </em></h2><h2><em> </em></h2><h2><em>Symbol: Mg </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 24 </em></h2><h2><em> </em></h2><h2><em>Protons: 12 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 12 </em></h2><h2><em> </em></h2><h2><em>Electrons: 12 </em></h2><h2><em> </em></h2><h2><em>Aluminum </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 13 </em></h2><h2><em> </em></h2><h2><em>Symbol: Al </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 27 </em></h2><h2><em> </em></h2><h2><em>Protons: 13 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 14 </em></h2><h2><em> </em></h2><h2><em>Electrons: 13 </em></h2><h2><em> </em></h2><h2><em>Silicon </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 14 </em></h2><h2><em> </em></h2><h2><em>Symbol: Si </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 28 </em></h2><h2><em> </em></h2><h2><em>Protons: 14 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 14 </em></h2><h2><em> </em></h2><h2><em>Electrons: 14 </em></h2><h2><em> </em></h2><h2><em>Phosphorus </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 15 </em></h2><h2><em> </em></h2><h2><em>Symbol: P </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 31 </em></h2><h2><em> </em></h2><h2><em>Protons: 15 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 16 </em></h2><h2><em> </em></h2><h2><em>Electrons: 15 </em></h2><h2><em> </em></h2><h2><em>Sulfur </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 16 </em></h2><h2><em> </em></h2><h2><em>Symbol: S </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 32 </em></h2><h2><em> </em></h2><h2><em>Protons: 16 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 16 </em></h2><h2><em> </em></h2><h2><em>Electrons: 16 </em></h2><h2><em> </em></h2><h2><em>Chlorine </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 17 </em></h2><h2><em> </em></h2><h2><em>Symbol: Cl </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 35 </em></h2><h2><em> </em></h2><h2><em>Protons: 17 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 18 </em></h2><h2><em> </em></h2><h2><em>Electrons: 17 </em></h2><h2><em> </em></h2><h2><em>Argon </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 18 </em></h2><h2><em> </em></h2><h2><em>Symbol: Ar </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 40 </em></h2><h2><em> </em></h2><h2><em>Protons: 18 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 22 </em></h2><h2><em> </em></h2><h2><em>Electrons: 18 </em></h2><h2><em> </em></h2><h2><em>Potassium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 19 </em></h2><h2><em> </em></h2><h2><em>Symbol: K </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 39 </em></h2><h2><em> </em></h2><h2><em>Protons: 19 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 20 </em></h2><h2><em> </em></h2><h2><em>Electrons: 19 </em></h2><h2><em> </em></h2><h2><em>Calcium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 20 </em></h2><h2><em> </em></h2><h2><em>Symbol: Ca </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 40 </em></h2><h2><em> </em></h2><h2><em>Protons: 20 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 20 </em></h2><h2><em> </em></h2><h2><em>Electrons: 20</em> </h2>

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How many moles of ammonla are produced by 2.8 mol of hydrogen.<br><br>ANH

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Answer:

3 i think

Explanation:

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2 years ago

Is 2 KNO₃ + H₂CO₃ → K₂CO₃ + 4 HNO₃ a balanced equation

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Hey there!

The elements in this equation are K, N, O, H, and C.

Let's count how many of each are on each side to see if it is balanced.

K: 2 on the left, 2 on the right.

<em>N: 2 on the left, 4 on the right. </em>

<em>O: 9 on the left, 6 on the right. </em>

<em>H: 2 on the left, 4 on the right. </em>

C: 1 on the left, 1 on the right.

Notice that there are different amounts of N, O, and H on the left side and the right side.

This means that the equation is not balanced.

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2 years ago

. the density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v). densit

ale4655 [162]

Density is intensive because it is the ratio of two extensive properties that is mass to volume.

<h3>What is Density ?</h3>

Density is defined as mass per unit volume. S.I unit if density is kg/m³.

It is expressed as

Density = $\frac{\text{Mass}}{\text{Volume}}$ or $d = \frac{m}{V}$

<h3>What is Intensive Property ? </h3>

Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.

Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.

<h3>What is Extensive property ?</h3>

Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.

Example of extensive property length, weight, volume, mass etc.

Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.

Learn more about Density here: brainly.com/question/1354972

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Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = $\frac{\text{Mass}}{\text{Volume}}$ or $d = \frac{m}{V}$

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

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1 year ago

If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th

qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

$K_c=4.74\times 10^4$

Concentration at equilibrium:

$[COBr_2]=1.58\times 10^{-6}M$

$[Co]=2.78\times 10^{-3}M$

$[Br_2]=2.51\times 10^{-5}M$

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

The expression for reaction quotient will be :

$Q=\frac{[CO][Br_2]}{[COBr_2]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}$

The given equilibrium constant value is, $K_c=4.74\times 10^4$

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When $Q>K_c$ that means product > reactant. So, the reaction is reactant favored.

When $Q$ that means reactant > product. So, the reaction is product favored.

When $Q=K_c$ that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the $Q$ that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

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2 years ago

Select the correct answer.

Karo-lina-s [1.5K]

Answer: OB

Explanation:

The empirical formula of an element is the simplest formula of an element which shows the ratios of atoms of the each element present in a molecule of a compound .

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2 years ago