How are insulators and conductors different?

At Alpha Centauri's surface, the gravitational force between Alpha Centauri and a 2 kg mass of hot gas has a magnitude of 618.2

sergeinik [125]

Answer:

6.86 * 10^8 m

Explanation:

Parameters given:

Mass of hot gas, m = 2 kg

Gravitational Force, F = 618.2 N

Mass of Alpha Centauri, M = 2.178 * 10^30 kg

The gravitational force between two masses (the hot gas and Alpha Centauri) , m and M, at a distance, r, given as:

F = (G*M*m) / r²

Where G = gravitational constant

Therefore,

618.2 = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / r²

=> r² = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / 618.2

r² = 4.699 * 10^17 m²

=> r = 6.86 * 10^8 m

We are told that the hot gas is on the surface of Alpha Centauri, hence, the distance between both their centers is the radius of Alpha Centauri.

The mean radius of Alpha Centauri is 6.86 * 10^8 m.

5 0

3 years ago

Read 2 more answers

A car is moving from rest and attained a velocity of 80 m/s. Calculate the acceleration of the car after 5 s?

soldi70 [24.7K]

Answer:

400 m/s

Explanation:

If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.

80 x 5 = 400

7 0

3 years ago

Consider two transformers. Transformer A has 300 turns on its primary and 500 turns on its secondary. Transformer B has 250 turn

rusak2 [61]

Answer:

Secondary voltage on second transformer is 200 volt.

Explanation:

It is given two transformer

Let us consider first transformer.

Number of turns in primary $N_p=300$

Numb er of turns in secondary $N_s=500$

Now consider second transformer

Number of turns in primary $N_p=250$

Number of turns in secondary $N_s=1000$

Now it is given that same voltage of 50 volt is applied to primary of both the transformer.

For second transformer

$\frac{N_p}{N_s}=\frac{V_p}{V_s}$

$\frac{250}{1000}=\frac{50}{V_s}$

$V_s=200volt$

So secondary voltage on second transformer is 200 volt

4 0

4 years ago

Which are two characteristics of a proton

Scilla [17]

Positive electric charge and found inside the nucleus

6 0

2 years ago

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The elevator accelerates upward (in the positive direction) from rest at a rate of 1.95 m/s2 for 2.15 s. Calculate the tension i

sammy [17]

The mass is missing. The mass of the elevator is 1650 kg.

Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

Acceleration in the upward direction (a) = 1.95 m/s²

Time taken by the elevator (t) = 2.15 s

Mass of the elevator and persons (m) = 1650 kg

Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

$F_{net}=T-mg$

Now, from Newton's second law, net force equals mass times acceleration.

$F_{net}=ma\\\\T-mg=ma\\\\T=m(g+a)$

Plug in the given values and solve for 'T'. This gives,

$T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N$

Therefore, the tension in the cable is 19387.5 N.

3 0

4 years ago