The magnetic moment is -
M = 5.5 x 
A
.
We have current carrying single circular loop placed in a magnetic field
parallel to the plane of the loop.
We have to determine the Magnetic moment of the loop.
<h3>What is the formula to calculate the magnetic moment of loop?</h3>
The formula to calculate the magnetic moment of the loop is -
M = NIA
where -
N - Number of turns
I - Current in the loop
A - Area of the loop
According to the question, we have -
I = 17mA = 0.017A
Circumference (C) = 2 meters
B = 0.8 T
Now -
C = 2
2
r = 2
r = 1
r = 
r = 0.32
Using the formula -
M = NIA
M = NI
M = 3.14 x 1 x 0.017 x 0.32 x 0.32
M = 3.14 x 4 x 0.017
M = 5.5 x A
Hence, the magnetic moment is -
M = 5.5 x A
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Answer:
Explanation: Here we have given a direct equation . There for no need to worry .
P = I²×R
P = (12)² ×100
P = 14400W = 14.4 kW
For second one
P = I² ×R
200 = I²×150
I = √200/150
I = 1.15 A
When any boat displaces a weight of water equal to its own weight, it floats. This is called the "principle of flotation": A floating object displaces a weight of fluid equal to its own weight.
Answer:
Questions involving accelerating objects, including those in free fall, can be solved using three equations
y = 1/2at2 + v0t + y0
v = v0 + at
vf2 = v02 + 2 a (y - y0)
In this case, only the first equation is needed.
Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2
Since the object is dropped, the initial velocity is 0.
0 = 1/2(-9.8)t2 + 370. t = sqrt(370/4.9) = 8.69 s
Explanation:
