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enot [183]
3 years ago
15

A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec. What is the ball's change in momentum?

Physics
2 answers:
kupik [55]3 years ago
8 0

Answer

The change in momentum of ball is 30kg m/sec .

Explanation:

Formula for change in momentum is given by .

\Delta P = mv -mu

Where m is mass , v is final velocity and u is initial velocity .

As given

A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec.

m = 3

u = 0 m/sec

v = 10 m/sec

Putting values in the formula

\Delta P = 3\times 10 -3\times 0

\Delta P = 30\ kg\ m/sec

Therefore the change in momentum of ball is 30kg m/sec .



valentina_108 [34]3 years ago
4 0
Change in Momentum =  mv - mu.

u = 0, v = 10 m/s.  Note ball accelerated from rest, so initial velocity = 0. u =0

Change in Momentum =  mv - mu = 3*10 - 3*0 =30.

Change in Momentum = 30 kgm/s.

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13.6 cm

Explanation:

From Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.

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sin θ = x / √(x² + 144)

Substituting:

3/4 = x / √(x² + 144)

9/16 = x² / (x² + 144)

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3 years ago
A baseball has mass 0.145 kg.
Vesnalui [34]

Answer:

a).p=15.67kg*m/s

b). F=7.83N

Explanation:

change in momentum is the subtraction from "after momentum" of the "before momentum"  as momentum is a vector quantity this is a vector subtraction.

initial momentum of ball

m1v1 = (0.145)(44.0) = 6.38 kg-m/s

after momentum

m1v2 = (0.145)(64.0) = 9.28 kg-m/s

since these momentums are 180° opposite one must be called negative so their difference

6.38+9.28= 15.67 kg-m/s

change in momentum = 15.67 kg-m/s ANS a1

Impulse = change in momenutm = 15.67 ANS a2

b)

Impulse =Favg*t

I=(2.00)Favg

Impulse from (a2) = 15.67  

Favg = 15.67/2.00 =

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3 0
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Answer:

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