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podryga [215]
2 years ago
7

A car is moving from rest and attained a velocity of 80 m/s. Calculate the acceleration of the car after 5 s?

Physics
1 answer:
soldi70 [24.7K]2 years ago
7 0

Answer:

400 m/s

Explanation:

If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.

80 x 5 = 400

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A 1,103 kg car traveling at 18 m/s to the south collides with a 4,919 kg truck that is initially at rest at a stoplight. The car
Zigmanuir [339]

ANSWER

3.30\text{ m/s}

EXPLANATION

Parameters given:

Mass of car, mc = 1103 kg

Mass of truck, mt = 4919 kg

Initial velocity of car, uc = 18 m/s

Inital velocity of truck = 0 m/s

To solve this problem, we have to apply the law of conservation of momentum, which states that the total momentum of a system is constant.

This implies that:

m_cu_c+m_tu_t=m_cv_c+m_tv_t

Since the car and the truck stick together after the collision, they will have the same final velocity.

Hence:

m_cu_c+m_tu_t=(m_c+m_t)v_{}_{}

Substitute the given values and solve for v (final velocity):

\begin{gathered} (1103\cdot18)+(4919\cdot0)=(1103+4919)v \\ \Rightarrow19854=6022v \\ \Rightarrow v=\frac{19854}{6022} \\ v=3.30\text{ m/s} \end{gathered}

That is the final velocity of the two-vehicle mass.

8 0
1 year ago
What is one main difference between animal cells and plant cells?
vekshin1

Answer:

No cell wall

Explanation:

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3 years ago
Move the red arrow onto the picture to show how you think warm air would move over this area of land and water on a dark cold ni
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There’s no pictures?
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Who invented the telephone?
krok68 [10]
<h2>Answer:</h2><h3><em><u>Alexander Graham Bell</u></em></h3><h2>Explanation:</h2>

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What must the charge (sign and magnitude) of a 3.45 g particle be for it to remain stationary when placed in a downward-directed
Pani-rosa [81]

     charge must be equal to 5.74 ×10⁻⁵

 In the question it is said that the particle remains stationary which means the the net force on the particle is zero. So, the counterbalancing forces must be equal which means weight is equal to upward electric force.

     →    Fnet =0

     →    mg =  qE

 substituting the values we get :

         0.00345 × 9.81 =  q × 590

   →       q = 5.74 ×10⁻⁵

    Hence the charge must be equal to   5.74 ×10⁻⁵.

   Learn more about charges here:

          brainly.com/question/26092261

                    # SPJ4

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2 years ago
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