Newton’s fifth law says so i’m sorry it’s just logic
Answer:
The samples specific heat is 14.8 J/kg.K
Explanation:
Given that,
Weight = 28.4 N
Suppose, heat energy 
Temperature = 18°C
We need to calculate the samples specific heat
Using formula of specific heat
Where, m = mass
c = specific heat
= temperature
Q = heat
Put the value into the formula
Hence, The samples specific heat is 14.8 J/kg.K
work is done by the pulling force which is same as the tension force in the rope. the net work done is zero for the crate since crate moves at constant velocity. but there is work done by the tension force which is equal in magnitude to the work done by the frictional force.
T = tension force in the rope = 115 N
d = displacement of the crate = 7.0 m
θ = angle between the direction of tension force and displacement = 37 deg
work done on the crate is given as
W = F d Cosθ
inserting the values given above
W = (115) (7.0) Cos37
W = 643 J
Answer:
1.196 m
Explanation:
Given the wave equation :
y= 0.05 cos(5.25x-1775t)
Recall the general traverse wave relation :
y(x, t) = Acos(kx - wt)
A = Amplitude
To Obtian the wavelength ;
We compare the both equations :
Take the value of k ;
kx = 5.25x
k = 5.25
Recall;
k = 2π/λ
5.25 = 2π/λ
5.25λ = 2π
λ = 2π / 5.25
λ = (2 * 3.14) / 5.25 = 1.196 m
