All categories

2 years ago

A car is moving from rest and attained a velocity of 80 m/s. Calculate the acceleration of the car after 5 s?

Physics

1 answer:

soldi70 [24.7K]2 years ago

7 0

Answer:

400 m/s

Explanation:

If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.

80 x 5 = 400

You might be interested in

Evaluate the scenarios and select the one that demonstrates the training principle overload.

matrenka [14]

Answer:

B :)

Explanation:

:) JUST TRUST ME I GOT IT CORRECT

5 0

3 years ago

Read 2 more answers

The force on a dropped apple hitting the ground depends upon

yulyashka [42]

Answer:

F=ma

Explanation:

Force = mass * acceleration

5 0

3 years ago

The center of mass of the system is the point at which the total mass of the system could be concentrated without changing the _

Sveta_85 [38]

The centre of mass of the system is the point at which the total

mass of system could be concentrated without changing the moment

of the system.

Centre of Mass is the point at which the whole mass of the system

is assumed to be concentrated.

The general formula for the COM is:

xₙ = Σmₐxₐ / Σmₐ where, a = 1,2,3.........n

Here the term Σ mₐ xₐ is called the first moment of the system and the

denominator expression is called total mass of the system.

Therefore, from this theory we can say that the moment of the system

remain unchanged while calculating the COM.

Hence, The centre of mass of the system is the point at which the total

mass of system could be concentrated without changing the moment

of the system.

learn more about centre of mass here:

brainly.com/question/3454419

#SPJ4

8 0

1 year ago

You are a member of an alpine rescue team and must get a box of supplies, with mass 3.00 kg , up an incline of constant slope an

Sever21 [200]

Answer:

v = 8.45 m/s

Explanation:

given,

mass = 3 kg

angle = 30.0°

vertical distance = 3.3 m

μ = 0.06

according to conservation of energy

KE(loss) = PE(gain) + Work done (against\ friction)..............(1)

frictional Force

$F_f = \mu N$

$F_f = \mu m g cos \theta$

work against friction

W = F d

$W = \mu m g cos \theta \times h l sin\theta$

$W = \dfrac{\mu m g \times h}{tan\theta}$

Potential energy

PE = mgh

$\dfrac{1}{2}mv^2= \dfrac{\mu mgh}{tan \theta}+ mgh$

$\dfrac{1}{2}v^2= \dfrac{0.06 \times 9.81 \times 3.3}{tan 30^0}+ 9.8\times 3.3$

v = 8.45 m/s

the minimum speed is equal to 8.45 m/s

6 0

3 years ago

a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh

Viefleur [7K]

Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing. Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

   F = (mass) · (speed)² / (radius).

For this particular car, the force is

(2,000 kg) · (25 m/s)² / (80 m)

   = (2,000 kg) · (625 m²/s²) / (80 m)

   = (2,000 · 625 / 80) (kg · m / s²)

   = 15,625 newtons .

5 0

3 years ago