Answer:
5446.8 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 50 g
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Specific heat capacity (C) = 0.89 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 192.4 – 70
ΔT = 122.4 °C
Finally, we shall determine the heat required to heat up the block of aluminum as follow:
Mass (M) = 50 g
Specific heat capacity (C) = 0.89 J/gºC
Change in temperature (ΔT) = 122.4 °C
Heat (Q) required =?
Q = MCΔT
Q = 50 × 0.89 × 122.4
Q = 5446.8 J
Thus, the heat required to heat up the block of aluminum is 5446.8 J
Acid palmitic acid has higher melting point, because it has two more methylene groups.
Acid palmitic acid has higher melting point, because it has two more methylene groups.
Giving it a greater surface area and therefore more intermolecular van der waals interact than the myristic acid.
stearic arid 
linoleic acid 
(two double bond)
Stearic acid has higher Melting point, because it does not have any Carbon-Carbon double bonds, whereas linoleic acid has two cis double bonds which prevent the molecules from packing closely together.
Oleic Acid and Linoleic acid.
-one double bond (cis)
Acid palmitic acid has higher melting point, because it has two more methylene groups.
For more such question on methylene group.
brainly.com/question/4279223
#SPJ4
Answer:
density of animal populations
Hope this helped
