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Triss [41]
3 years ago
11

Reaction of (r)-2-chloro-4-methylhexane with excess nai in acetone gives racemic 2-iodo-4-methylhexane. what is the explanation

that best describes this transformation?
Chemistry
1 answer:
saveliy_v [14]3 years ago
4 0

I believe this question has the following five choices to choose from:

 

>an SN2 reaction has occurred with inversion of configuration

>racemization followed by an S N 2 attack

>an SN1 reaction has taken over resulting in inversion of configuration

>an SN1 reaction has occurred due to carbocation formation

>an SN1 reaction followed by an S N 2 “backside” attack

 

 

The correct answer is:

an SN1 reaction has occurred due to carbocation formation 

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Answer:

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Explanation:

From the question we are told that

    The equation is  2 Cr  +  3Pb^{2+} \to 3Pb + 2Cr^{3+}

     The  temperature is  T = 25^oC =  298 K   [room  \ temperature ]

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Generally for an  electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as  

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Here  n  is  the no of electron  with value n = 6

       F  is  the Faraday's constant with value 96487 J/V

  =>   G =  6  * 96487 *  0.61

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This Gibbs free energy can also be represented mathematically as

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Here  R  is the cell constant with value 8.314J/K

           K is the equilibrium constant

From above

=>  K  =  antilog^{\frac{G}{ RT} }

Generally  antilog =  2.718

=>K  =  2.718^{\frac{3.5 *10^5}{ 8.314* 298} }

=>   K  =  8*10^{61}

       

         

       

         

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