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ladessa [460]
3 years ago
10

If I have 2.4g of magnesium, how many g of oxygen(O2 ) will I need to react completely with the magnesium? 2Mg +O2 → MgO

Chemistry
1 answer:
Jet001 [13]3 years ago
5 0

Explanation:

just trying....hope that helps

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How many carbon atoms are in each mole of calcium carbonate?
xeze [42]

Answer:

5 atoms are in each molecule of calcium carbonate

6 0
3 years ago
How many grams of oxygen is needed to completely react with 9.30 moles of aluminum
Orlov [11]
Balanced chemical equation:

* moles of oxygen

4 Al + 3 O2 = 2 Al2O3

4 moles Al -------------- 3 moles O2
9.30 moles Al ---------- moles O2

moles O2 = 9.30 * 3 / 4

moles O2 = 27.9 / 4 => 6.975 moles of O2

Therefore:

Molar mass O2 = 31.9988 g/mol

n = m / mm

6.975 = m / 31.9988

m = 6.975 * 31.9988

m = 223.19 of O2


5 0
3 years ago
The nucleus of a lead atom has a charge of 82 protons what are the drection and magnitude
KATRIN_1 [288]

Answer:

left

Explanation:

7 0
3 years ago
The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas
Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

PV=n_1RT

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

n_1 = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(9.61atm)\times (3.06L)=n_1\times RT

n_1=\frac{29.4}{RT}

Now we have to calculate the moles of oxygen gas.

PV=n_2RT

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

n_2 = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(1.75atm)\times (6.65L)=n_2\times RT

n_2=\frac{11.6}{RT}

Now we have to determine the final pressure in the system after mixing the gases.

P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}

where,

P_{total} = final pressure of gas = ?

V_{total} = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}

P_{total}=4.22atm

Therefore, the final pressure in the system is 4.22 atm.

4 0
3 years ago
1.
xenn [34]
The answer is OH.

Hope this helps!
4 0
3 years ago
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