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2 years ago

A car travels at an average speed of 52 miles per hour. How long does it take to travel 234 miles

Mathematics

1 answer:

mars1129 [50]2 years ago

7 0

Speed = distance/time

so to work out time you do distance/ speed

234/52= 4.5hours

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How would you write the equation with a slope of 2/3 and a y-intercept of (0,-3)?

rosijanka [135]

Answer:

y = (2/3)x - 3

Step-by-step explanation:

Slope-intercept form: y = mx + b

Note that:

y = (x , y)

m = slope

x = (x , y)

b = y-intercept.

The point is given to you. Note that:

(x , y) = (0 , -3) ∴

x = 0

y = -3

The slope = m = 2/3

Plug in the corresponding numbers to the corresponding variable:

y = mx + b

-3 = (2/3)(0) + b

-3 = 0 + b

b = -3

Plug in -3 for b in the equation:

y = mx + b

y = (2/3)x -3

y = (2/3)x - 3 is your equation.

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3 years ago

The sink in Josh’s art studio measures 16 inches by 15 inches by 6 inches. A second sink used just for paint brushes has a simil

marin [14]

Linear scale factor =1/2
volume scale factor=(1/2)³=1/8
the volume of the larger figure will be:
volume=length*width*height
volume=16×15×6
volume=1440 cubic inches
thus volume of the small sink will be:
1/8×1440
=180 cubic inches

3 0

2 years ago

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

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3 years ago

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kakasveta [241]

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Corresponding Angles postulate is ur answer mate

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