1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slava [35]
2 years ago
14

6. Transformations were applied to the square

Mathematics
1 answer:
Artyom0805 [142]2 years ago
4 0

Here we want to find an equation for a function given that we know it is a transformation of the square root parent function and that it passes through the point (3, 8).

We will see that the new function can be: g(x) = √x +  9.732

<h3>Transformations of functions</h3>

We define a transformation of a function f(x) as an operator that, when applied to the function, changes it in some way. Some transformations will move the graph of f(x), some will shrink it, some will reflect it.

In this case, we know that we have:

f(x) = √x

And we apply a transformation to this, generating g(x), such that:

g(3) = 8.

Let's assume that the transformation is a vertical shift, this means that we just add a constant to f(x), so we get:

g(x) = f(x) + k

Using what we know, we can write:

g(3) = f(3) + k = 8

        √3 + k = 8

                 k = 8 + √3 = 9.732

Then the new function can be:

g(x) = √x +  9.732

This represents a vertical shift of 9.732 units up, meaning that we "moved" the graph of f(x) by  9.732 units upwards.

If you want to learn more about transformations, you can read:

brainly.com/question/4289712

You might be interested in
Any 10th grader solve it <br>for 50 points​
kkurt [141]

Answer:

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., a_{1}=A and common difference=D

The nth term can be written as

a_{n}=A+(n-1)D

pth term of given arithmetic progression is a

a_{p}=A+(p-1)D=a

qth term of given arithmetic progression is b

a_{q}=A+(q-1)D=b and

rth term of given arithmetic progression is c

a_{r}=A+(r-1)D=c

We have to prove that

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0

Now to prove LHS=RHS

Now take LHS

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)

=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)

=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)

=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}

=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}

=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

\neq 0

ie., RHS\neq 0

Therefore LHS\neq RHS

ie.,\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  

Hence proved

5 0
3 years ago
The pair of linear equations 2x-3y = 14 and 3x - 2y = 4 has solution(s).<br><br>answer plz....​
Lesechka [4]

Answer:

2x -3y =1 and 3x-2y= 4 has

Step-by-step explanation:

The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.

a1/a2= 2/3

b1/b2= 3/-2 (-) cancle so it remains

c1 / c2 = 1/4

a1/a2 = b1/b2 not equal to c1/c2 as no solution

8 0
3 years ago
40 points PLZ HELP!
tiny-mole [99]

Answer:

178

Step-by-step explanation:

4 0
3 years ago
Write the polynomial in standard form 7x+3+5x^2
natka813 [3]
It’s should 5x^2+7x+3 in standard form
5 0
2 years ago
Solve for C and please show work
Zanzabum

Use the law of cosines:

c² = 8² + 11² - 2•8•11 cos(37°)

c² ≈ 44.4402

c ≈ 6.66634

4 0
2 years ago
Other questions:
  • Is 85 prime or composite
    6·1 answer
  • The price of a jet ski was marked up 15% over the previous year's model. if the previous year's model sold for $500, what is the
    7·1 answer
  • Shane's money is 3:11 if Isabella has 33 dollars how much do shane and Isabella have together
    6·1 answer
  • What is the value of 2.8 liters in milliliters?
    6·1 answer
  • The formula for surface area of a cube is 65, where s is the side length of the cube. If the side length of a cube is 4 centimet
    12·1 answer
  • Use induction to prove: For every integer n &gt; 1, the number n5 - n is a multiple of 5.
    14·1 answer
  • A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 614 babies bo
    11·1 answer
  • What is the answer?? What number replaces b? Measuring angles
    15·1 answer
  • Harry works in a local computer store and he kept a record of the number of computers sold each month for the past year. How man
    7·1 answer
  • Which expression is equivalent to 3^0x3^-3?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!