MathsWatch Question Please Help

Mathematics

1 answer:

elena-s [515]2 years ago

5 0

Answer:

940 grams

Step-by-step explanation:

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What is an angle that is supplementary to

finlep [7]

Answer: GCE

Step-by-step explanation:

This is because supplementary angles add up to 180 degrees. By assuming GCE is 70 degrees, and GCE is 110 degrees, we get 180 degrees. Plus, both of those angles share the same vertex.

6 0

1 year ago

How to evaluate question number 4

ANTONII [103]

There are 2 ways that spring to mind.

One is to use the definition of the derivative at a point:

$f'(c)=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}$

In this case, $c=0$ and $f(x)=\sqrt{5-x}$ . Then

$f'(x)=-\dfrac1{2\sqrt{5-x}}\implies f'(0)=\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\dfrac1{2\sqrt5}$

- - -

If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

$\dfrac{\sqrt{5-x}-\sqrt5}x\cdot\dfrac{\sqrt{5-x}+\sqrt5}{\sqrt{5-x}+\sqrt5}=\dfrac{\left(\sqrt{5-x}\right)^2-\left(\sqrt5\right)^2}{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac x{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac1{\sqrt{5-x}+\sqrt5}$