n = number of moles of sample of octane = 0.07 mol
Q = energy absorbed by a sample of octane = 3.5 x 10³ J
c = molar heat capacity of octane = 254.0 J/K* mol
ΔT = increase in temperature of octane = ?
Heat absorbed is given as
Q = n c ΔT
inserting the values
3.5 x 10³ J = (0.07 mol) (254.0 J/K* mol) ΔT
ΔT = (3.5 x 10³ )/((0.07) (254.0))
ΔT = 196.85 K
hence increase in temperature comes out to be 196.85 K
Answer:
An element is a substance that cannot be split out into simpler substance by chemical means
A compound i is a substance consisting atoms of 2 or more different elements and these atoms are chemically joined together
Explanation:
Answer:
2.1056L or 2105.6mL
Explanation:
We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:
Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol
Mass of Na2CO3 = 10g
Mole of Na2CO3 =.?
Mole = mass /molar mass
Mole of Na2CO3 = 10/106
Mole of Na2CO3 = 0.094 mole
Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:
Na2CO3 + 2HCl —> 2NaCl + H2O + CO2
From the balanced equation above,
1 mole of Na2CO3 reacted to produce 1 mole of CO2.
Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.
Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:
1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.
Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L
Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL
Answer:
2 significant figures i.e. 2 and 7.
Explanation:
We need to find the number of significant figures in the given number i.e. 
.
It has 2 significant figures i.e. 2 and 7.
It means the power of 10 doesn't count in the significant figures.
Hence, there are 2 significant figures.
I think that pressure will affect the solubility of gasses the most. The reason why I think this is that gasses are affected the most by pressure change. By definition solids and liquids are not easily affected by pressure by how close the molecules are to each other in both of those phases.
I hope this helps. Please let me know if you have any further questions or need any clarification.
