Hey there!:
absorbance = log 100 - log Transmitance
absorbace = 0.85
log 100 = 2
- log transmitance = absorbace / log 100
0.85 / 2= 0.425
transmitance = 10 ^ ( - 0.425 )
transmitance = 0.376
This
electronic transition would result in the emission of a photon with the highest
energy:
4p
– 2s
<span>This
can be the same with the emission of 4f to 2s which would emit energy in the
visible region. The energy in the visible region would emit more energy than in
the infrared region which makes this emission to have the highest energy.</span>
I believe the answer is C) both
Hope this helps
it turns yellow to orange
