Twice a number x excced 5 by at least 4, find all possible value of X
1 answer:
Answer:
x > 4.5
Step-by-step explanation:
Twice a number x = 2 * x
must exceed 5 by at least 4 = 2 * x > 5 by at least 4 = 2* x > 5 + 4
Twice a number x (2*x) must exceed 5 (>5) by at least 4 (+4)
2* x > 5 + 4
2x > 9
divide both sides by 2 to isolate x
x > 4.5
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.:|:. Answer .:|:.
4 13/16
.:|:. Explanation .:|:.
11 / 4 * 7 / 4
11 * 7
4 * 4
77 / 16
Simplify:
4 13/16
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First, you want to set up a proportion.
8/24 = 10/y
Cross multiply to get
240 = 8y, then divide 8 from both sides to get y = 30.
Answer: C
Explanation: 8^2 + 15^2 = 17^2
64+225=289
5x10^5 + 6x10^3 + 7x10^3 + 9x10^-1 expanded form
five hundred six thousand seven hundred nine. No "and" because that would denote a decimal.