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2 years ago

Technician A says that to start a fuel-injected car, the accelerator should be depressed

Engineering

1 answer:

Bumek [7]2 years ago

7 0

Answer:

Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A

Explanation:

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How much work is required to move an electron from the positive terminal to the negative terminal of a 12 V battery? (Knight 21.

Ray Of Light [21]

Answer:

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

W = -4μJ

Explanation:

Work required to move the charge

W = qΔV

initial point V₁ = 150V

Final point V₂ = -50V

W = q(V₂ -V₁)

= 20 × 10⁹(-50 - 150)

W = -4μJ

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

6 0

3 years ago

Find the second derivative of: y = sqrt(x + 4)/4; x ≥ -4.

hammer [34]

Answer: $\dfrac{-1}{16(x+4)^{\frac{3}{2}}}$

Explanation:

Given

$y=\dfrac{\sqrt{x+4}}{4}\\\text{differentitate w.r.t x}\\\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{1}{4}\times \dfrac{1}{2\sqrt{x+4}}=\dfrac{1}{8\sqrt{x+4}}$

$\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{(x+4)^{-0.5}}{8}$

Again differentiate for the second derivative

$\frac{\mathrm{d^2} y}{\mathrm{d} x^2}=\dfrac{1}{8}\times \dfrac{-1}{2(x+4)^{\frac{3}{2}}}=\dfrac{-1}{16(x+4)^{\frac{3}{2}}}$

8 0

4 years ago

Read 2 more answers

After Hurricane Katrina there was considerable public outrage that many of the properties were not insured against flooding alth

Mashcka [7]

I would say B is the answer

8 0

4 years ago

Read 2 more answers

A closed, rigid, 0.45 m^3 tank is filled with 12 kg of water. The initial pressure is p1 = 20 bar. The water is cooled until the

liberstina [14]

Answer:

initial quality = 0.3690

heat transfer = 979.63 kJ/kg

Explanation:

Given data:

volume of tank 0.45^3

weight of water 12 kg

Initial pressure 20 bar

final pressure 4 bar

Specific volume $v = \frac {0.45}{12} = 0.0375 m^3/kg$

At Pressure = 20 bar, from saturated water table

$v_f = 0.01177 m^/kg$

$v_g = 0.099587 m^3/kg$

$x = \frac{v -v_f}{v_g -v_f} = \frac{0.0375 - 0.001177}{0.099587 - 0.001177}$

inital quality is x =0.3690

Heat transfer is calculated as

$u_1 = h_f + x(h_g - h_f) = v_f + x( h_{fg})$

from saturated water table, for pressure 20 bar ,

$h_f = 908.79 kJ/kg, h_{fg} = 1890.7 kJ/kg$

=908.79 + 0.0357(1890.7)

= 979.63 kJ/kg

7 0

3 years ago

A circle has an area of 153.86 in squared what’s the radius of the circle

sweet [91]

Answer: 49

Explanation: So, how you figure this out is by taking the area of the circle (153.86) and dividing it by pi (3.14) which equals 49 which is your answer! So, the <u>radius of the circle is </u><u>49</u>.

If you need any further instruction or help let me know!

6 0

3 years ago