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3 years ago

Where is a machinist most likely to work?

Engineering

2 answers:

vova2212 [387]3 years ago

6 0

Answer:

definitely factory

Explanation:

qwelly [4]3 years ago

3 0

Answer:

Absolutely the factory

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Which option identifies the most likely scaling factor in the above drawing of the Mercury capsule and booster unit? 1:1,000 1:1

Elina [12.6K]

Answer:

I would say 10000;1 but thats just me

Explanation:

3 0

3 years ago

A circular bar is 800mm in length and 32mm in diameter. The bar is made from a material with a modulus of elasticity E = 150 GPa

Yuki888 [10]

Answer:

For any material if ∈ is the axial strain then the lateral strain is given by -μ∈ is the lateral strain in the object

Where,

μ is the poisson's ratio of the material

The longitudinal strain is calculated as follows

$\varepsilon _{axial}=\frac{\Delta length}{Length_{original}}\\\\\therefore \varepsilon _{axial}=\frac{0.7}{800}=8.75\times 10^{-4}$

Thus the lateral strain becomes

$\varepsilon _{lateral}=-\mu\varepsilon _{axial}\\\\\varepsilon _{lateral}=-0.27\times 8.75\times 10^{-4}=-2.36\times 10^{-4}$

now by definition of lateral strain we have

$\varepsilon _{lateral}=\frac{\Delta diameter}{diameter_{original}}\\\\\Rightarrow \Delta Diameter=-2.36\times 10^{-4}\times 32=-7.56\times 10^{-3}\\\\D_{f}-D_{i}=-7.56\times 10^{-3}\\\\D_{f}=32-7.56\times 10^{-3}=31.992mm$

By hookes law the stress developed due to the given strain is given by

$\sigma =\varepsilon _{axial}E$

Applying values we get

$\sigma =8.75\times 10^{-4}\times 150\times 10^{9}\\\\\sigma =131.25MPa$

Thus the force is calculated as

$Force=\sigma \times Area\\\\Force=131.25\times 10^{6}\times \frac{\pi (32\times 10^{-3})^{4}}{4}\\\\Force=105.55kN$

5 0

3 years ago

Which of the following elements would make a good insulator?

Ainat [17]

Answer:

Glass

Explanation:

Please mark me the brilliant

8 0

2 years ago

if you’re disassembling a master cylinder and the front piston assembly is stuck in the master cylinder you can

lianna [129]

Answer:

Put water in the cylinder then push the piston inward

Explanation:

When water is put it displaces all the air making it possible for the piston to be pulled easier and without distraction

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3 years ago

This operating mode assists steering return after completing a turn.

castortr0y [4]

Answer:

In return mode, the system assists steering return after completing a turn. Information from the steering position sensor prevents the system from overshooting the center position. In dampener mode, the system acts like a hydraulic dampener to prevent kick back and bump steer.

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2 years ago