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3 years ago

Which happens when a wave passes through an opening

Engineering

2 answers:

Nookie1986 [14]3 years ago

7 0

Reflecting

Explaining

Alina [70]3 years ago

5 0

Reflect diffration that’s the answer

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Water flows through a converging pipe at a mass flow rate of 25 kg/s. If the inside diameter of the pipes sections are 7.0 cm an

ser-zykov [4K]

Answer:

volumetric flow rate = $0.0251 m^3/s$

Velocity in pipe section 1 = $6.513m/s$

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the volume will be mass/density

25/997 = $0.0251 m^3/s$

volumetric flow rate = $0.0251 m^3/s$

Average velocity calculations:

Pipe section A:

cross-sectional area =

$\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2$

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

$velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s$

Pipe section B:

cross-sectional area =

$\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2$

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

$velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s$

7 0

3 years ago

Technician A says that 18 gauge AWG wire can carry more current flow that 12 gauge AWG wire. Technician B says that metric wire

denpristay [2]

Answer:

Technician B

Explanation:

Both AWG and metric are sized by cross-sectional area.

Technician A is wrong: 12 gauge wire is larger diameter rated for 20 amps in free air. 18 awg is smaller diameter and typically used for speaker wiring, Class II or low voltage and sub-circuits within appliances.

6 0

3 years ago

A spur gearset has a module of 6 mm and a velocity ratio of 4. The pinion has 16 teeth. Find the number of teeth on the driven g

levacccp [35]

Answer:

NG=64 teeth

dG=384mm

dP=96mm

C=240mm

Explanation:

step one:

given data

module m=6mm

velocity ratio VR=4

number of teeth of pinion Np=16

Step two:

Required

1. Number of teeth on the driven gear

$N_G=N_P*V_R\\\\N_G=16*4\\\\N_G=64$

The driven gear has 64 teeth

2. The pitch diameters

The driven gear diameter

$d_G=N_G*m\\\\d_G=64*6\\\\d_G=384$

The driven gear diameter is 384mm

The pinion diameter

$d_P=N_P*m\\\\d_P=16*6\\\\d_P=96$

Pinion diameter is 96mm

3. Theoretical center-to-center distance

$C=\frac{d_G+d_P}{2} \\\\C=\frac{384+96}{2} \\\\C=\frac{480}{2}\\\\C=240$

The theoretical center-to-center distance is 240mm

5 0

3 years ago

Plz answer all of these questions!

statuscvo [17]

Answer: all you need to to is go to help me with this question.cm

Explanation:

5 0

3 years ago

The benefit of using the generalized enthalpy departure chart prepared by using PR and TR as the parameters instead of P and T i

Butoxors [25]

The answer is: a. True

5 0

3 years ago