The answer is 29029
10000+19000+20+9=29029
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
v=5.42m/s
Step-by-Step Explanation:
We can use conservation of energy to solve this
mgh=1/2mv^2
2gh=v^2
v=sqrt(2gh)
v=sqrt[2*9.8m/s^2*(6.5-5)]
v=5.42m/s
Answer:
its 3rd graph, the one with (-1,0) point
