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3 years ago

Let a function y represent the water level in a harbor measured in meters, and let x represent the number of hours

Mathematics

1 answer:

svp [43]3 years ago

6 0

Answer:

2.2 hours

Step-by-step explanation:

The equation to graph is

4.5cos(4pi/25 x)+15

Find amplitude by subtracting min from max and dividing it by two. a=4.5

Find vertical shift k by finding the midline. Either add 4.5 to 10.5 or subtract 4.5 from 19.5. k = 15

The period is given to be 12.5. Use formula 2pi/b = period to find b. b = 4pi/25

Put the equation into graphing calculator and find what x equals when the graph is 17 (for the first time)

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Step-by-step explanation:

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2 years ago

Can someone please help I can't solve this problem!!!!!!!!!!!

notsponge [240]

Answer:

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Step-by-step explanation:

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2 years ago

Solve the equation 4(3y-1)-3(2y)=6

olga nikolaevna [1]

Answer:

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Remove backets

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3 years ago

Three eighths of the students in a class of 32 students are boys. How many students are boys?

nata0808 [166]

12 because 1/8 is 4 4x3= 12

4 0

3 years ago

Read 2 more answers

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago