A pole vaulter rested a 17 foot pole against a wall. If the top of the pole hit the wall 14 feet above the ground, how far from
the wall is the bottom of the pole
1 answer:
Answer:
a = √93
a ≈ 9.64
Step-by-step explanation:
We can use the Pythagorean theorem for this: a² + b² = c²
c is given as the hypotenuse, which is the pole with a length of 17 ft
c² is 17²
b is a leg with a height of 14 ft
b² = 14²
We need to find the base leg, a, distance from the wall to the base of the pole.
Solve:
a² + 14² = 17²
a² + 196 = 289
a² = 93
a = √93
-Chetan K
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