Answer:
The enrollment drop is 12 students per year. The equation is 60=5d. The complete sentence would be the enrollment drop at the after school program dropped 12 students per year, and the equation is 60=5d
Step-by-step explanation:
So I will start with explaining the equation. 60 is the amount of students that dropped, 5 is the year, and d is the enrollment drop rate per year that you are trying to find. The way to use this equation is to isolate d. To do that you divide both sides of the equation by 5, this leaves you with 12 = d. Therefore your yearly enrollment drop is 12 students.
60 = 5d
60/5 = d
60/5 = 12
12 = d
Hopefully this explained your answer.
Answer: Choice D. P = i/rt
This is the same as saying P = i/(rt). The parenthesis are preferred in my opinion to indicate we have rt in the denominator and not just r.
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Explanation:
In the original equation, prt is the same as p*r*t. So we multiply p, r and t to get prt.
This can be thought of as p*(rt). To isolate p, we undo the multiplication done to the variable p. We will divide both sides by rt to get
i = prt
i = p*(rt)
i/(rt) = p*(rt)/(rt) ... dividing both sides by rt
i/(rt) = p
p = i/(rt)
Answer:
2. There are 5 students 14 years old 7 grade
So the rule with multiplying exponents of the same base is
. Apply this rule here:

Next, the rule with converting negative exponents into positive ones is
. Apply this rule here:

<u>Your final answer is 1/49.</u>
<h2>------------------------------------------------</h2>
So an additional rule when it comes to exponents is ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
In this case, your fractional exponent, x^9/7, would be converted to
. However, I had just realized you can further expand this.
Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:
![\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7Bx%5E9%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%2Ax%5E2%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D%20)
Your final answer would be ![x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20x%5Csqrt%5B7%5D%7Bx%5E2%7D%20)