The gcf of 15 and 10 is 5
Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
Answer:
1. 7% change increase
2. 27%change decrease
3. 39% change decrease
4. 29% change increase
Step-by-step explanation:
I hope this is right
Well first do you parentheses and the multiply all of your exponets
Step-by-step explanation:
i.1+y<25
y<25-1
y<24
ii.101+6y>200
6y>200−101
6y>99
y>99/6
y>33/2
