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Inessa [10]
2 years ago
14

Coefficient of x^2 in the expansion of (x-3)^3

Mathematics
2 answers:
Mila [183]2 years ago
7 0

Answer:

-9

Step-by-step explanation:

(x-3)(x-3)(x-3)

(x^2-6x+9)(x-3)

x^3-9x^2+27x-27

Therefore, the coefficient of x^2 is -9.

Romashka [77]2 years ago
7 0

Answer:

-9

Step-by-step explanation:

=> (x-3)³

=> (x-3)(x-3)(x-3)

=> (x²-6x+9)(x-3)

=> x³-3x²-6x²+18x+9x-27

=> x^3-9x^2+27x-27

<u><em>So, the coefficient of x² is -9</em></u>

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Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: between the midpoints of segments AP and QB
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Answer:

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Step-by-step explanation:

AB = a

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And we know QB = \frac{AP}{2}

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Now midpoint of AP = \frac{a}{2} × \frac{1}{2} = \frac{a}{4}

and midpoint of QB = \frac{a}{4} × \frac{1}{2} = \frac{a}{8}

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= \frac{a}{8}

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