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3 years ago

- Saint Pauls Mid

1 answer:

4 0

It should be noted that the median is the middle number in a sorted form whether ascending or descending while the interquartile range tells one the spread of the middle half of the distribution.

<h3>Solving median and interquartile range.</h3>

Your information is incomplete. Therefore, an overview will be given. To find the median, arrange the numbers given in an ascending or descending order and the middle number is the median.

Also, you can count how many numbers you've. If you have an odd number, divide the numbers by 2 and then round up in order to get the position of the median. In a case where it's an even number, divide it by 2 and go the number in the position and average it with the number that's in the next higher position in order to get the median.

In order to find the interquartile range, let's assume that the given numbers are 48, 52, 57, 64, 72, 76, 77, 81, 85, and 88. We've then numbers and this can be grouped into 5 each.

The first 5 will be 48, 52, 57, 64, and 72. In this case, the median in the first half which is Q1 is 57. The second 5 will be 76, 77, 81, 85, and 88. The median in the second half which is Q2 is 81. Therefore, the interquartile range will be:

= Q3 - Q1

= 81 - 57

= 24

Learn more about median and interquartile range on:

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

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3 years ago

Which graph represents function f? f(x) = (1/3)^x

weqwewe [10]

Answer:

The second group represents function f.

Step-by-step explanation:

Hope it helps...

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3 years ago

Daniela is a stain glass artist; she created the window below for her living room. What is

OLga [1]

The window has a shape of a semi-circle (half of a circle).

We know the diameter d = 12 ft.

The area of a (complete) circle is given by the formula:
A = π × r²

The radius can be found by halving the diameter:
r = d ÷ 2
= 12 ÷ 2
= 6 ft

Therefore the area of the circle will be:
A = π × r²
= 3.14 × 6²
= 3.14 × 36
= 113.04 ft²

And the area of the semi-circle:
A = 113.04 ÷ 2
= 56.52 ft²

Hence, the area of the window will be 56.52 ft².

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3 years ago

Can some one solve 2 I’ll give a crown

vitfil [10]

Answer:

Hi! The correct answer is 16!

Step-by-step explanation:

~Use the formula (b/2)^2 in order to create a new term to complete the square~

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3 years ago

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