Question

53 = x ^{2} + 10x " align="absmiddle" class="latex-formula">
please answer.. ​

Answer 1

Answer:

$\huge\underline\color{pink}{Answer ☘}$

$153 = x {}^{2} + 10x \\ x {}^{2} + 10x - 153 = 0 \\ \\ using \: quadratic \: formula... \\ \\ x = \frac{ - b \: ± \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ a = 1\\ b = 10\\ c = - 153 \\ \\ x = \frac{ - 10 \: ± \: \sqrt{10 {}^{2} - 4 \times 1 \times ( - 153)} }{2 \times 1} \\ x = \frac{ - 10 \: ± \: 2 \sqrt{178} }{2} \\ \\ x = \frac{ - 10 + 2 \sqrt{178} }{2} \\ or \\ x = \frac{ - 10 - \sqrt{178} }{2} \\ \\ x = - 5 \: ± \: \sqrt{178}$

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