S=56, u=0, v=33, a=?, t=3.4
v=u+at
33=3.4 a
a = 9.7m/s^2
Answer:
t = 1.68 min
S = 2.82 miles
Explanation:
Given,
The initial velocity of the vehicle, u = 0
The final velocity of the vehicle, v = 203 mph
The average acceleration of the vehicle, a = 2.93 ft/s²
= 7191.82 miles/h²
Using the first equation of motion
v = u + at
t = (v - u) / a
= (203 - 0) / 7191.82
= 0.028 h
= 100.8 s
Thus, the time taken by the vehicle to reach the final velocity is, t = 100.8 s
Using the third equations of motion
S = ut + 1/2 at²
Substituting the values
S = 0.5 x 7191.82 x (0.028)²
= 2.82 miles
Hence, the distance traveled by the vehicle, S = 2.82 miles
So I am assuming that by "the following," you mean in general terms.
The shortest wavelength of the spectrum is the Gamma Ray waves, they are 400nm and are the most deadly, because of how often and frequent they are able to vibrate. Shorter the wavelength the more active.
So the list from "shortest," to "longest," is,
Gamma Ray, X-Ray, Ultraviolet, Visible, Infrared, Microwave, and Radio wavelengths.
In the spectrum, Radio has the longest and furthest traveling waves. This means that they are not harmful and that they can travel extreme distances.
Hope this helps!
Answer:
The velocity at exit of the nozzle is 175.8 m/s
Solution:
As per the question:
Air density inside the rocket,
Speed, v = 1.20 m/s
The inner diameter of the rocket,
The inner radius of the rocket,
The exit diameter of the nozzle,
The exit radius of the nozzle,
Air density inside the nozzle,
Now,
To calculate the air speed when it leaves the nozzle:
Mass rate in the interior of the rocket,
Mass rate in the outlet of the nozzle,
Now,
Now,
We know that:
v' = 175.8 m/s