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postnew [5]
3 years ago
13

Air is flowing through a rocket nozzle. Inside the rocket the air has a density of 5.25 kg/m3 and a speed of 1.20 m/s. The inter

ior diameter of the rocket is 15.0 cm. At the nozzle exit, the diameter is 2.50 cm and the density is 1.29 kg/m3. What is the speed of the air when it leaves the nozzle? Air is flowing through a rocket nozzle. Inside the rocket the air has a density of 5.25 kg/m3 and a speed of 1.20 m/s. The interior diameter of the rocket is 15.0 cm. At the nozzle exit, the diameter is 2.50 cm and the density is 1.29 kg/m3. What is the speed of the air when it leaves the nozzle? 45.7 m/s 29.3 m/s 88.0 m/s 123 m/s 176 m/s
Physics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

The velocity at exit of the nozzle is 175.8 m/s

Solution:

As per the question:

Air density inside the rocket, \rho_{i} = 5.25\ kg/m^{3}

Speed, v = 1.20 m/s

The inner diameter of the rocket, d_{i} = 15.0\ cm = 0.15\ m

The inner radius of the rocket, r_{i} = \frac{0.15}{2} = 0.075\ m

The exit diameter of the nozzle, d_{e} = 2.50\ cm = 0.025\ m

The exit radius of the nozzle, r_{e} = 0.0125\ m

Air density inside the nozzle, \rho_{n} = 1.29\kg/m^{3}

Now,

To calculate the air speed when it leaves the nozzle:

Mass rate in the interior of the rocket, \frac{dM}{dt} = \rho_{i}Av

Mass rate in the outlet of the nozzle, \frac{dm}{dt} = \rho_{n}A'v'

Now,

A = \rho_{i}r_{i}^{2}

Now,

We know that:

Av = A'v'

\rho_{i}r_{i}^{2}v = \rho_{n}r_{e}^{2}v'

5.25\times 0.075^{2}\times 1.2 = 1.29\times 0.0125^{2}v'

v' = 175.8 m/s

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6 0
3 years ago
A cassette recorder uses a plug-in transformer to convert 120 V to 12.0 V, with a maximum current output of 200 mA. What is the
goldfiish [28.3K]

Answer:

20 mA

Explanation:

We have given that the transformer convert 120 V to 12 V means it is a step down transformer

The turn ratio of the transformer is given as a=\frac{N_1}{N_2}=\frac{V_1}{V_2}=\frac{120}{12}=10 here V_! is primary voltage and V_2 is secondary voltage

As the voltage decreases from primary to secondary so current will increase from primary to secondary

We have given output current that is secondary current so primary that is input current will be less

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4 0
3 years ago
a car goes from a velocity zero to a velocity of 15 meters per second East in 2.1 seconds. What is the car's acceleration?
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31.5 would be the acceleration.
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3 years ago
A small car has a head-on collision with a large truck. Which of the following statements concerning the magnitude of the averag
andrey2020 [161]

Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

The second one says that:

F = m*a

force equals mass times acceleration.

And the third one says that;

"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"

From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.

But this seems odd, because we would expect to see the car being more affected by the impact, right?

Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

such that M > m

Then for the small car we have:

F = m*a

And for the truck:

F = M*a'

Because the force is the same for both of them, we can write:

m*a = M*a'

a = (M/m)*a'

because M > m, then M/m > 1.

This means that the acceleration that the car experiences is larger than the acceleration for the truck, and this is why we would see that the car seems more affected by the impact, regardless of the fact that both vehicles experience the same force in the impact.

6 0
2 years ago
A sound wave, with speed of 340 m/s has a frequency of 17,000 Hz. What
Fiesta28 [93]
Wavelength = speed / frequency = 340 / 17000 = 0.02 m
6 0
3 years ago
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