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postnew [5]
3 years ago
13

Air is flowing through a rocket nozzle. Inside the rocket the air has a density of 5.25 kg/m3 and a speed of 1.20 m/s. The inter

ior diameter of the rocket is 15.0 cm. At the nozzle exit, the diameter is 2.50 cm and the density is 1.29 kg/m3. What is the speed of the air when it leaves the nozzle? Air is flowing through a rocket nozzle. Inside the rocket the air has a density of 5.25 kg/m3 and a speed of 1.20 m/s. The interior diameter of the rocket is 15.0 cm. At the nozzle exit, the diameter is 2.50 cm and the density is 1.29 kg/m3. What is the speed of the air when it leaves the nozzle? 45.7 m/s 29.3 m/s 88.0 m/s 123 m/s 176 m/s
Physics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

The velocity at exit of the nozzle is 175.8 m/s

Solution:

As per the question:

Air density inside the rocket, \rho_{i} = 5.25\ kg/m^{3}

Speed, v = 1.20 m/s

The inner diameter of the rocket, d_{i} = 15.0\ cm = 0.15\ m

The inner radius of the rocket, r_{i} = \frac{0.15}{2} = 0.075\ m

The exit diameter of the nozzle, d_{e} = 2.50\ cm = 0.025\ m

The exit radius of the nozzle, r_{e} = 0.0125\ m

Air density inside the nozzle, \rho_{n} = 1.29\kg/m^{3}

Now,

To calculate the air speed when it leaves the nozzle:

Mass rate in the interior of the rocket, \frac{dM}{dt} = \rho_{i}Av

Mass rate in the outlet of the nozzle, \frac{dm}{dt} = \rho_{n}A'v'

Now,

A = \rho_{i}r_{i}^{2}

Now,

We know that:

Av = A'v'

\rho_{i}r_{i}^{2}v = \rho_{n}r_{e}^{2}v'

5.25\times 0.075^{2}\times 1.2 = 1.29\times 0.0125^{2}v'

v' = 175.8 m/s

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40
insens350 [35]

Answer:

774.8 secs

Explanation:

distance(d)= speed(v)* time(t)

calculate speed:

refractive index = speed of light (c)/ speed of light in medium (v)

1.56 = 3*10^8*v

v=192307692.3 m/s

d = v *t

t = d/v

on substituting values:

t = 774.8 secs

4 0
2 years ago
A 150 g baseball is traveling horizontally at 50 m/s. If the ball takes 20 ms to stop once it is in contact with the catcher’s g
Sliva [168]
To solve for force, you need to get the product of mass and acceleration. 
F = ma

Your given is:
m = 150g
a = ?
v = 50 m/s
t = 20ms

As you can see, you do not have acceleration yet. But if you read the problem you can come up with the formula of acceleration. 
Acceleration is the change in velocity over a period of time.

a = change in velocity/time

To get the change in velocity, you get the difference between the initial velocity and final velocity:

a =  \frac{vf-vi}{t}

The ball was moving initially at a velocity of 50 m/s and it came to a stop. This is your clue. If a ball comes to a stop then that means that the final velocity of the ball is 0 m/s. 

So we can put it into our formula now:

a = \frac{0m/s-50m/s}{20ms}

WAIT! As you can see, the units do not match. We have ms and s into our equation and that means you cannot proceed till they are the same. First we need to convert ms to s. 

20ms x \frac{1s}{1000ms} = \frac{20s}{1000} = 0.02s

So your new time is 0.02s. Now we put this time into the formula:


a = \frac{0m/s-50m/s}{0.02s}
a =  \frac{-50m/s}{0.02s}  = -2,500 m/ s^{2}

As you can see our acceleration is a negative value, this indicates that it decelerated or slowed down which makes sense because it was brought to a stop. 

So now we have our acceleration. Now using this, we can get our force. 

F= ma

Before we start doing this, you need to take note that the unit of force is N, but when you expand it, it is kg.m/ s^{2} but as you can see our mass given is in grams. So again, before you put them into the equation we need to change it into kg first. 

150g =  \frac{1kg}{1,000g}  =  \frac{150kg}{1,000}  = 0.150kg

Our new mass is 0.150kg. 

To make things clearer, let us write down all our new values:

m = 0.150kg
a = -2,500 m/ s^{2}

Now that all our units match, we can put that into our formula:

F= ma
F= (0.150kg)(-2,500m/s^{2})
F = -375kg.m/ s^{2}  or -375N

The value again is negative because it is going against the initial direction of the ball. But if your instructor just wants to get the value of force or the magnitude of the force, just disregard the sign. 



4 0
3 years ago
A space ship to the moon covered the 216,000 km in 72 hours. What was it’s average velocity
Dahasolnce [82]

Answer:3000km/h

Explanation:

speed=distance/time

216,000km/72hrs

=3000km/h

8 0
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