Answer:
Class width = 20
Approximate lower class limit of the first class = 110
Approximate Upper class limit of the first class = 119
Step-by-step Explanation:
The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.
Thus, class width = 130 - 110 = 20
The approximate lower class limit of the first class is the lowest score we have in the first class = 110
The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129
They are parallel and if you have more questions like this a good website to help you answer desmos graphing calculator
Answer:
One solution
Step-by-step explanation:
x+y=5
3x-y=-5
Add the equations together will get you:
4x=0
Divide the 0 by 4 to get the x alone will get you
x=0
Hey there! :)
Answer:
Domain: (-∞, ∞)
Range: [-1, ∞)
Step-by-step explanation:
This is an absolute-value function. (Graphed below) The vertex is at (-3, -1) which consists of the minimum y-value of the function. Therefore:
Domain: (-∞, ∞)
Range: [-1, ∞)
The parabola vertex is (1,5), the focus of the parabola is (1,6), and the directrix y = 4.
<h3>What is the graph of a parabolic equation?</h3>
The graph of a parabolic equation is a U-shape curve graph that is established from a quadratic equation.
From the given information:
![\mathbf{y=\dfrac{1}{4}(x-1)^2+5}](https://tex.z-dn.net/?f=%5Cmathbf%7By%3D%5Cdfrac%7B1%7D%7B4%7D%28x-1%29%5E2%2B5%7D)
The vertex of an up-down facing parabolic equation takes the form:
y = ax² + bx + c is ![\mathbf{x_v = -\dfrac{b}{2a}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx_v%20%3D%20-%5Cdfrac%7Bb%7D%7B2a%7D%7D)
Rewriting the given equation:
![\mathbf{y = \dfrac{x^2}{4}-\dfrac{x}{2}+\dfrac{21}{4}}](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B4%7D-%5Cdfrac%7Bx%7D%7B2%7D%2B%5Cdfrac%7B21%7D%7B4%7D%7D)
![\mathbf{x_v = -\dfrac{b}{2a}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx_v%20%3D%20-%5Cdfrac%7Bb%7D%7B2a%7D%7D)
![\mathbf{x_v = -\dfrac{(-\dfrac{1}{2})}{2(\dfrac{1}{4})}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx_v%20%3D%20-%5Cdfrac%7B%28-%5Cdfrac%7B1%7D%7B2%7D%29%7D%7B2%28%5Cdfrac%7B1%7D%7B4%7D%29%7D%7D)
![\mathbf{x_v =1}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx_v%20%3D1%7D)
Replacing the value of x into the equation, y becomes:
![\mathbf{y_v = 5}](https://tex.z-dn.net/?f=%5Cmathbf%7By_v%20%3D%205%7D)
Thus, the parabola vertex is (1,5)
From the vertex, the focus of the parabola is (1,6), and the directrix y = 4.
The graphical representation of the parabola is seen in the image attached below.
Learn more about the graph of a parabolic equation here:
brainly.com/question/12896871
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