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DerKrebs [107]
3 years ago
13

Solve the simultaneous equations

Mathematics
2 answers:
satela [25.4K]3 years ago
7 0
I use the substitution method, but you can also use elimination and matrix

1. Solve for y in 3x+y=14
y=14-3x

2. Substitute y=14-3x into x+2y=3
-5x+28=3

3. Solve for x in -5x+28=3
x=5

4. Substitute x=5 into y=14-3x
y=-1

5. Therefore,
x=5
y=-1

Have a nice day :D
Iteru [2.4K]3 years ago
5 0
You can use a bunch of different methods here, but I'll use substitution.

For the second equation, you can bring the 2y to the right side to isolate the x:

x=-2y+3

You can then substitute this into the first equation to find out y:

3x+y=14
3(-2y+3)+y=14
-6y+9+y=14
-5y=5
y=-1

Now you can plug in y to the second equation to find x:

x=-2y+3
x=-2(-1)+3
x=2+3
x=5

Therefore:
x=5
y=-1
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Answer:

18245

Step-by-step explanation:

We have to use L.C.M,

L.C.M(20,24,32,38)

2|20,24,32,38

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L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19

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Now for each case remainder is 5,

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Answer:

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Step-by-step explanation:

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