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Svetlanka [38]
3 years ago
8

How much work is done by a student carrying a 12 kg backpack while accelerating at a rate of 0.51 m/s2 over a distance of 5.0 m?

Physics
1 answer:
Klio2033 [76]3 years ago
8 0

The amount of work done by the student in carrying the backpack is 30.6 J

<h3>Definition of workdone </h3>

Workdone is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = Force (F) × distance (d)

Wd = Fd

Also,

Force (F) = mass (m) × acceleration (a)

F = ma

Therefore,

Wd = (ma) × d

With the above formula, we can obtain the work done by the student.

<h3>How to determine the Workdone </h3>

From the question given above, the following data were obtained:

  • Mass (m) = 12 Kg
  • Acceleration (a) = 0.51 m/s²
  • Distance (d) = 5 m
  • Workdone (Wd) =?

Wd = (ma) × d

Wd = 12 × 0.51 × 5

Wd = 30.6 J

Learn more about workdone:

brainly.com/question/14667371

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How much energy is needed to move an electron in a hydrogen atom from the ground state (n = 1) to n = 3?
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The energy needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3 will be 1.93 *10^-18J and 12.09 eV.

<h3>How to compute the value?</h3>

The following can be deduced:

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En = -13.6 /n2 eV

where n is principal quantum number of orbit.

Energy of electron in first orbit = E1 = -13.6 / 12 = - 13.6eV

Energy of electron in third orbit = E3 = -13.6 /32 = -1.51 eV

Energy required to move an electron fromfirst to thirdorbit ΔE = E3- E1

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Complete question:

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