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Svetlanka [38]
3 years ago
8

How much work is done by a student carrying a 12 kg backpack while accelerating at a rate of 0.51 m/s2 over a distance of 5.0 m?

Physics
1 answer:
Klio2033 [76]3 years ago
8 0

The amount of work done by the student in carrying the backpack is 30.6 J

<h3>Definition of workdone </h3>

Workdone is defined as the product of force and distance moved in the direction of the force.

Work done (Wd) = Force (F) × distance (d)

Wd = Fd

Also,

Force (F) = mass (m) × acceleration (a)

F = ma

Therefore,

Wd = (ma) × d

With the above formula, we can obtain the work done by the student.

<h3>How to determine the Workdone </h3>

From the question given above, the following data were obtained:

  • Mass (m) = 12 Kg
  • Acceleration (a) = 0.51 m/s²
  • Distance (d) = 5 m
  • Workdone (Wd) =?

Wd = (ma) × d

Wd = 12 × 0.51 × 5

Wd = 30.6 J

Learn more about workdone:

brainly.com/question/14667371

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Ultraviolet light from a distant star is traveling at 3.0 × 108 m/s. how long will it take for the light to reach earth if it mu
castortr0y [4]

Given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

<h3>What is Speed?</h3>

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

  • Speed of the Ultraviolet light c = 3.0 × 10⁸m/s = 1.08 × 10⁹km/h
  • Distance it must cover d = 4.0 × 10¹³km
  • Time elapsed t = ?

We substitute our given values into the expression above.

Speed = Distance ÷ time

1.08 × 10⁹km/h = 4.0 × 10¹³km ÷ t

t = 4.0 × 10¹³km ÷ 1.08 × 10⁹km/h

t = 3.7 × 10⁴ hrs

Therefore, given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

Learn more about speed here: brainly.com/question/7359669

#SPJ4

5 0
2 years ago
A 0.55 kg projectile is launched from the edge of a cliff with an initial kinetic energy of 1550 J and at its highest point is 1
SCORPION-xisa [38]

Answer:

a). 53.78 m/s

b) 52.38 m/s

c) -75.58 m

Explanation:

See attachment for calculation

In the c part, The negative distance is telling us that the project went below the lunch point.

5 0
3 years ago
A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w
son4ous [18]

Answer:

5773.50269 Hz

23 A

Explanation:

L = Inductance = 6 mH

C = Capacitance = 5 μF

R = Resistance = 3 Ω

\epsilon = Maximum emf = 69 V

Resonant angular frequency is given by

\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz

The resonant angular frequency is 5773.50269 Hz

Current is given by

I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A

The current amplitude at the resonant angular frequency is 23 A

7 0
3 years ago
Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
Dovator [93]
It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
3 0
3 years ago
Read 2 more answers
3. Discuss the main purpose of Experiment" Explain the greatest advantage of experiment in psychology?
Scrat [10]

Answer:

Social psychologists utilize experimental techniques to study how people are influenced by groups. Health psychologists rely on experimentation and research to better understand the factors that contribute to wellness and disease.

Explanation:

7 0
3 years ago
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