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Daniel [21]
3 years ago
13

A boat has a velocity of 5m/s North with respect to a river. It aims to reach point A, directly north across the river, which is

40 m wide. However, because of the river speed it reaches another point
b. If the speed of the current is 2m/s to the east, calculate the time of the trip and the distance between points A and
b.
Physics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
What are the answer

Need the answers 
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If measuring experimental results, what can you predict about the work output of a 1200 Watt hair dryer?
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A satellite is put in a circular orbit about Earth with a radius equal to 35% of the radius of the Moon's orbit. What is its per
Debora [2.8K]

Answer:

0.21 lunar month

Explanation:

the radius of moon = r₁

time period of the moon = T₁ = 1 lunar month

The radius of the satellite = 0.35 r₁

Time period of satellite

The relation between time period and radius

              T\ \alpha\ \sqrt{r^3}

now,

              \dfrac{T_2}{T_1}=\dfrac{\sqrt{r_2^3}}{\sqrt{r_1^3}}

              \dfrac{T_2}{T_1}=\dfrac{\sqrt{0.35^3r_1^3}}{\sqrt{r_1^3}}

              \dfrac{T_2}{1}=\sqrt{0.35^3}

                              T₂ = 0.21 lunar month

hence, the time period of revolution of satellite is equal to 0.21 lunar month

6 0
3 years ago
A 35-year-old patent clerk needs glasses of 50-cm focal length to read patent applications that he holds 25 cm from his eyes. Fi
Natali5045456 [20]

Answer:

28.57 cm

Explanation:

We are given that

Focal length,f=50 cm

Distance of application from his eyes,s=40 cm

\frac{1}{s}+\frac{1}{s'}=\frac{1}{f}

\frac{1}{40}+\frac{1}{s'}=\frac{1}{50}

\frac{1}{s'}=\frac{1}{50}-\frac{1}{40}=\frac{4-5}{200}

s'=\frac{200}{-1}=-200 cm

s=25 cm

Substitute the values

\frac{1}{25}-\frac{1}{200}=\frac{1}{f'}

\frac{8-1}{200}=\frac{1}{f'}

\frac{1}{f'}=\frac{7}{200}

f'=\frac{200}{7}=28.57 cm

6 0
3 years ago
A flute player hears four beats per second when she compares her note to a 523 Hz tuning fork (the note C). She can match the fr
xxTIMURxx [149]

Answer:

527Hz

Explanation:

The beat frequency of any two waves is:

Fbeat =|f1 – f2|

i.e  

for frequency tied to length increase (wavelength increases as length increases, therefore frequency decrease::    Fbeat = f1+f2

for frequency tied to length decrease wavelength increases as length increases, therefore frequency also increases :    Fbeat = f1-f2

Note that a wavelength increase means a decrease of frequency because v = fλ

Therefore from the question:

Fbeat  =4 beats/s

F2 -523Hz

Fbeat = f1-f2

F1=Fbeat+F2

=523+4

=527Hz

   

6 0
2 years ago
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