Answer:
0.21 lunar month
Explanation:
the radius of moon = r₁
time period of the moon = T₁ = 1 lunar month
The radius of the satellite = 0.35 r₁
Time period of satellite
The relation between time period and radius

now,



T₂ = 0.21 lunar month
hence, the time period of revolution of satellite is equal to 0.21 lunar month
Answer:
28.57 cm
Explanation:
We are given that
Focal length,
Distance of application from his eyes,s=40 cm




s=25 cm
Substitute the values




Answer:
527Hz
Explanation:
The beat frequency of any two waves is:
Fbeat =|f1 – f2|
i.e
for frequency tied to length increase (wavelength increases as length increases, therefore frequency decrease:: Fbeat = f1+f2
for frequency tied to length decrease wavelength increases as length increases, therefore frequency also increases : Fbeat = f1-f2
Note that a wavelength increase means a decrease of frequency because v = fλ
Therefore from the question:
Fbeat =4 beats/s
F2 -523Hz
Fbeat = f1-f2
F1=Fbeat+F2
=523+4
=527Hz