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vagabundo [1.1K]
3 years ago
8

Water exhibits hydrogen bonding. Which option describes what this indicates about water?Water will generally require less energy

for a phase change compared to a similar substance without hydrogen bonds.Water will generally have a lower melting point compared to a similar substance without hydrogen bonds.Water will generally require more energy for a phase change compared to a similar substance without hydrogen bonds.Water will generally have a lower boiling point compared to a similar substance without hydrogen bonds.
Chemistry
1 answer:
Tems11 [23]3 years ago
5 0

The option that best describes water is : ( C ) Water will generally require more energy for a phase change compared to a similar substance without hydrogen bonds.

The hydrogen bonding present in water is due to the dipole-dipole interaction present with the hydrogen atom bonded to an electronegative oxygen atom which lies with the vicinity of the hydrogen atom.

Hydrogen bonding occurs mainly due to the difference in electronegativity between the oxygen and hydrogen atoms which makes the atoms partially negative and partially positive. The presence of Hydrogen bonding in a substance raises the melting and boiling points of the substance as well.

Hence we can conclude that The option that best describes water is : Water will generally require more energy for a phase change compared to a similar substance without hydrogen bonds.

Learn more about Hydrogen bonds : brainly.com/question/2161098

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Answer:

Explanation:

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heat absorbed = mass x specific heat x fall in temperature

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= 531.5 J .

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lattice energy = enthalpy of hydration + enthalpy change

= 2630 + 26.575

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3 years ago
A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon
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Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

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