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algol [13]
3 years ago
11

Which substance has a molar mass of 133.3 g? BaCl2 P2O5  AlCl3 MgCl2

Chemistry
2 answers:
sammy [17]3 years ago
4 0
The answer is AlCl3, it’s 133.34g/mol
DerKrebs [107]3 years ago
3 0
The answer is AlCl3 which has the molar mass of 133.34 g/mol
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Hydrogen bromide decomposes when heated to 437C according to the equation: 2HBr(g) H2(g) Br2(g). If the reaction starts with 2.1
iren [92.7K]

Answer:

<h3>the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>

Explanation:

Amount of HBr dissociated

2.15 \ mole \times \frac{36.7}{100} \\\\=0.789 \ mole

                                  2HBr(g)        ⇆          H2(g)           +          Br2(g)

Initial Changes          2.15                             0                                0  (mol)

                                - 0.789                      + 0.395                     + 0.395 (mol)

At equilibrium        1.361                            0.395                         0.395 (mole)

Concentration        1.361 / 1                   0.395 / 1                      0.395 / 1

at equilibrium (mole/L)

K_c=\frac{[H_2][Br_2]}{[HBr]^2} \\\\=\frac{(0.395)(0.395)}{(1.361)^2} \\\\=\frac{0.156025}{1.852321} \\\\=0.084

<h3>Therefore, the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>
6 0
3 years ago
A gas at 42. 0°c occupies a volume of 1. 32 l. if the volume increases to 2. 24 l, what is the new temperature in kelvin?
Nina [5.8K]

the answer is 534.54 kelvin

8 0
2 years ago
Part A In a particular experiment at 300 ∘C, [NO2] drops from 0.0138 to 0.00886 M in 374 s . The rate of disappearance of NO2 fo
sweet-ann [11.9K]

Answer:

The rate of disappearance of NO_2 for this period is-1.32\times 10^{-5} M/s

Explanation:

Initial concentration of NO_2 = x = 0.0138 M

Final concentration of NO_2 = y = 0.00886 M

Time elapsed during change in concentration = Δt = 374 s

Change in concentration ,\Delta [NO_2]= y - x = 0.00886 - 0.0138 M = -0.00494 M

The rate of disappearance of NO_2 for this period is:

\frac{\Delta [NO_2]}{\Delta t}=\frac{-0.00494 M}{374 s}=-1.32\times 10^{-5} M/s

4 0
3 years ago
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