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I am Lyosha [343]
2 years ago
11

The milliliter is a metric unit for

Chemistry
1 answer:
kifflom [539]2 years ago
6 0

Answer:

volume because milliliters are a measuring unit, but it is a very small amount

E x p l a n a t i o n :

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2) Which one<br>more active in between<br>Li and Na and why ?<br>IS​
Blababa [14]

Explanation:

what's li and na stand for ?

3 0
3 years ago
Read 2 more answers
How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?
gulaghasi [49]

Answer:

\boxed {\boxed {\sf 10.2 \ kJ}}

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

q=mc \Delta T

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

  • ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

  • ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

  • m= 225 g
  • c= 0.897 J/g° C
  • ΔT= 50.5 °C

q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)

Multiply the first two numbers. The units of grams cancel.

q= (225 \ g  * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)

q= (225   * 0.897 \ J / \textdegree C)(50.5 \textdegree C)

q= (201.825\ J / \textdegree C)(50.5 \textdegree C)

Multiply again. This time, the units of degrees Celsius cancel.

q= 201.825 \ J * 50.5

q= 10192.1625 \ J

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

\frac { 1  \ kJ}{ 1000 \ J}

Multiply by the answer we found in Joules.

10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}

10192.1625  * \frac{ 1 \ kJ}{ 1000 }

\frac {10192. 1625}{1000} \ kJ

10.1921625 \ kJ

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

10.2 \ kJ

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0
3 years ago
According to the law of constant composition, how many grams of oxygen does this isolated sample contain?
KatRina [158]

The Mass of oxygen in isolated sample is 8.6 g

<h3>What is the Law of Constant composition?</h3>

The law of constant composition states that pure samples of the same compound contain the same element in the same ratio by mass irrespective of the source from which the compound is obtained.

Considering the given ascorbic acid samples:

Laboratory sample contains 1.50 gg of carbon and 2.00 gg of oxygen

mass ratio of oxygen to carbon is 2 : 1.5

Isolated sample will contain 2/1.5 * 6.45 g of oxygen.

Mass of oxygen in isolated sample = 8.6 g

In conclusion, the mass of oxygen is determined from the mass ratio of oxygen and carbon in the compound.

Learn more about the Law of Constant composition at: brainly.com/question/1557481

#SPJ1

Note that the complete question is given below:

A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Another sample of ascorbic acid isolated from citrus fruits contains 6.45 gg of carbon. According to the law of constant composition, how many grams of oxygen does this isolated sample contain?

Express the answer in grams to three significant figures.

8.47 g

8 0
2 years ago
Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water. 3 no2(g) + h2o(ℓ) −→ 2 hno3(ℓ) + no(g) if 85
Naya [18.7K]
The balanced equation for the above reaction is as follows;
3NO₂ + H₂O --> 2HNO₃ + NO
stoichiometry of NO₂ to NO is 3:1
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
volume of gas is directly proportional to number of moles of gas.
therefore stoichiometry can be applied for volume as well.
volume ratio of NO₂ to NO is 3:1
volume of NO₂ reacted - 854 L
therefore volume of NO formed - 854 L /3 = 285 L
volume of NO formed - 285 L
8 0
3 years ago
If 3.1 moles of potassium chloride react with oxygen, how many moles of potassium chlorate would be produced?
Likurg_2 [28]

Answer: 19 dollar fortnite card Explanation:who wants it

7 0
3 years ago
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