The correct answer is Sulfur (S).
Sulfur has 6 valence electrons because it is located in Group 16 (or the sixth group over if you don’t count the transition metals). This means that one atom of sulfur has 6 electrons in its outermost shell out of 8 total “spots”, which you can count by counting the group numbers (excluding the transition metals) from Group 1 (with one valence electron) to Group 18 (the noble gases with full valence or outer shells).
By this same logic, Carbon (C) has 4 valence electrons and Cesium (Cs) has 1 valence electron, so neither of these is the correct answer.
Hope this helps!
Answer:
The partial pressure of CO₂ will decrease.
Explanation:
The reaction:
2CO (g) + O₂ (g) ⇄ 2CO₂ (g) has a ΔH = –566 kJ/mol. As ΔH<0, the reaction is exothermic.
Le Chatelier's principle says that if a system in chemical equilibrium is subjected to a disturbance it tends to change in a way that opposes this disturbance.
In this case, with increasing of the temperature, the system will produce less heat, doing the equilibrium shifts to the left.
Thus, the partial pressure of both CO and O₂ will increase. And<em> partial pressure of CO₂ will decrease.</em>
I hope it helps!
Only when it is found in the atmosphere, because it will create a hole, letting strong UV rays shine down on earth, heating it up, and causing skin cancer in humans and other animals.
We will use the formula for freezing point depression :
but first, we need to get the molality m of the solution:
- molality m = moles of C2H5OH / mass of water Kg
when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH
= 11.85 g / 46 g/mol
= 0.258 moles
and when we have the mass of water Kg = 0.368 Kg
so, by substitution on the molality formula:
∴ molality m = 0.258 moles / 0.368 Kg
= 0.7 mol/Kg
and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1
and when Kf is given = 1.86 C/m
so by substitution on ΔTf formula:
when ΔTf = i Kf m
∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg
= 1.302 °C
