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3 years ago

Solve the formula for the specified variable. V=AQT for A

Mathematics

1 answer:

Nitella [24]3 years ago

6 0

Answer:

$A = \frac{V}{QT}$

Step-by-step explanation:

To solve the problem you want to have A on one side, everything else on the other side. You can move over the variables by divind them from each side as shown:

$AQT = V$

$AQT = \frac{V}{1}$

$AQ = \frac{V}{T}$

$A = \frac{V}{QT}$

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4 years ago

Solve: 2x+7/5 - x-3/10 = x+1/15<br>find the value of x and verify the result will RHS

choli [55]

Step-by-step explanation:

<h3><u>Given Question :- </u></h3>

Solve for x :-

$\dfrac{2x + 7}{5} - \dfrac{x - 3}{10} = \dfrac{x + 1}{15}$

$\red{\large\underline{\sf{Solution-}}}$

Given linear equation is

$\rm :\longmapsto\: \dfrac{2x + 7}{5} - \dfrac{x - 3}{10} = \dfrac{x + 1}{15}$

$\rm :\longmapsto\: \dfrac{2(2x + 7) - (x - 3)}{10} = \dfrac{x + 1}{15}$

$\rm :\longmapsto\: \dfrac{4x + 14 - x + 3}{10} = \dfrac{x + 1}{15}$

$\rm :\longmapsto\: \dfrac{(4x - x) + (14 + 3)}{10} = \dfrac{x + 1}{15}$

$\rm :\longmapsto\: \dfrac{3x + 17}{10} = \dfrac{x + 1}{15}$

On multiply by 5 on both sides,

$\rm :\longmapsto\: \dfrac{3x + 17}{2} = \dfrac{x + 1}{3}$

On cross multiplication, we get

$\rm :\longmapsto\:3(3x + 17) = 2(x + 1)$

$\rm :\longmapsto\:9x +51 = 2x + 2$

$\rm :\longmapsto\:9x - 2x = 2 - 51$

$\rm :\longmapsto\:7x = - 49$

$\bf\implies \:x = - 7$

<h3><u>VERIFICATION</u></h3>

Consider, LHS

$\red{\rm :\longmapsto\: \dfrac{2x + 7}{5} - \dfrac{x - 3}{10}}$

On substituting the value of x, we get

$\red{\rm \: = \: \dfrac{2( - 7) + 7}{5} - \dfrac{ - 7 - 3}{10}}$

$\red{\rm \: = \: \dfrac{ - 14 + 7}{5} - \dfrac{ - 10}{10}}$

$\red{\rm \: = \: \dfrac{ - 7}{5} + 1}$

$\red{\rm \: = \: \dfrac{ - 7 + 5}{5}}$

$\red{\rm \: = \: \dfrac{ - 2}{5}}$

Consider RHS

$\green{\rm :\longmapsto\:\dfrac{x + 1}{15}}$

On substituting the value of x, we get

$\green{\rm \: = \: \dfrac{ - 7 + 1}{15}}$

$\green{\rm \: = \: \dfrac{ - 6}{15}}$

$\green{\rm \: = \: \dfrac{ - 2}{5}}$

$\rm \implies\:LHS=RHS$

HENCE, VERIFIED

5 0

3 years ago

Read 2 more answers

Quadrilateral ABCD is inscribed in circle 0 What is m<A

valentinak56 [21]

We know that
A quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary. ( Inscribed Quadrilateral Theorem)
so
m∠B+m∠D=180°
2x+(3x-5)=180
5x=180+5
5x=185
x=185/5
x=37°

m∠A=x+5-----> 37+5------> 42°

the answer is
m∠A is 42°

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3 years ago

Add or Subtract.<br> (−2^2 − 4 + 13) + (12^2 + 2 − 25)<br><br> (7^2 + 4 − 26) − (−7^2 − 3 + 15)

aleksklad [387]

Here is your answer

1. (−2^2 − 4 + 13) + (12^2 + 2 − 25)

= (4-4+13)+ (144+2-25)

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= 13+ (146-25)

=13+121

= 134

2. (7^2 + 4 − 26) − (−7^2 − 3 + 15)

= (49+4-26) - (49-3+15)

= 49 +4 -26 -49 +3 -15

= 7-41

= -34

HOPE IT IS USEFUL

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3 years ago

Mrs Cobb makes and sells her own apple-cranberry juice. In pitcher A, she mixed 4

meriva

If you put them into fractions you get 4/3 and 3/2

Now let's give them the same denominator.

3*2=6 and vice versa

So let's multiply the numerators by the same numbers

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3 years ago