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Nostrana [21]
3 years ago
12

Draw a visual representation to show eleven hundredths

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0
Make a rectangle that is 10 squares by 10 squares and color in 11 squares.
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Solve the quadratic equation (2x+5)(2x-5)
mote1985 [20]
If you want to multiply (2*x + 5) and (2*x - 5), you can do this using the following steps:

(2*x + 5) * (2*x - 5) = 4*x^2 - 10*x + 10*x - 25 = 4*x^2 - 25

The correct result is 4*x^2 - 25.
4 0
3 years ago
LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )
Dimas [21]
143 / 6x+12 = 132 / 72
143 / 6x+12 = 11 / 6

crossmultiply:
66x + 132 = 858
66x = 726
x = 11
8 0
2 years ago
Read 2 more answers
In science class, a student is measuring the temperature of a solution in science experiment. The solution
Radda [10]

Answer:

-11.8

Step-by-step explanation:

<u>Given:</u>

-3.4 to 12.4        increased  (difference = 15.8)

12.4 to 20.4      decreased (difference = 8)

20.4 to 3.2        increased  (difference = 17.2)

<u>To find:</u>

Final temperature.

Solution:

As we noticed, this is a pattern of increase, decrease, increase... (and so on and so forth). From this alone, we have gotten the clue that the temperature is going to decrease. But here is the thing, How far will it decrease?

Use the difference of the starting result to find the ending result.

3.2 - 15

= -11.8

Therefore, the final temperature is -11.8.

6 0
2 years ago
PLEASE can anyone help me with this problem??
Lilit [14]

9514 1404 393

Answer:

  4

Step-by-step explanation:

To find the value of g(7), locate 7 on the x-axis. Follow the grid line upward until it meets the graph (blue line). At that point, follow the grid line to the left until it meets the y-axis. Read the value from the scale on the y-axis.

  g(7) = 4

5 0
3 years ago
In 2000, the population of Big Springs was 13 thousand. Use the given doubling
trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is  t =0.

Formula:

A= A_0e^{rt}

Where,

A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year

for doubling time,

r = \frac{log (2)}{t} \\

r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007

Given value:

A = A_0e^{rt} \\\\

A_0 = 13000

t= 40 \ years

when year is 2000, t=0 so, year is 2100 year as t = 100.

A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4

7 0
3 years ago
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