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3 years ago

Solve for x. Round to the nearest tenth, if necessary....pleaseeeee help me with this lol.

Mathematics

1 answer:

insens350 [35]3 years ago

7 0

Based on the information given, it has been calculated that they value of x will be 0.9646.

<h3>Solving triangles</h3>

Based on the information given, it should be noted that the sine formula will be used.

Therefore, the equation to solve the question will be:

Sin 16° = x/3.5

x = Sin 16° × 3.5

x = 0.2756 × 3.5

x = 0.9646

Learn more about triangles on:

brainly.com/question/17335144

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Solve for y, give the slope and y intercept 5y=20, -y + 3=15x, y +1/3x=17

qaws [65]

$5y=20$ Equation

$y=4$ Divide by 5 on both sides

$5(4)=20$ Plug in for y

$20=20$ Simplify

y=4
slope= 0
y-intercept= 4

$^{-}y+3=15x$ Equation

$^{-}y=15x-3$ Subtract 3 from both sides

$y=-15x+3$ Divide both sides by -1

$- (^{-}15x+3) +3=15x$ Plug in for y

$15x-3+3=15x$ Distribute -1 into the parenthesis

$15x=15x$ Further simplified

y= -15x+3
slope= -15
y-intercept= 3

$y+ \frac{1}{3}x=17$ Equation

$y=^{-}\frac{1}{3}x+17$ Subtract 1/3x from both sides

$(^{-}\frac{1}{3}x+17 )+\frac{1}{3}x =17$ plug in for y

$17=17$ Simplify

y= -1/3x+17
slope= -1/3
intercept= 17

8 0

3 years ago

What is 1/2 2/3 1/4 and 5/6 in least to greatest

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1/2, 2/3, 1/4, 5/6 = 6/12, 8/12, 3/12, 10/12 = 1/4, 1/2, 2/3, 5/6

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3 years ago

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4 years ago

A school is designing two rectangular parking lots. The second parking lot is being designed so that its perimeter is 3/4 of per

Nataly [62]

The perimeter of second plot is 180 feet

<em><u>Solution:</u></em>

Given that,

The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot

<h3><u>Find the perimeter of first plot:</u></h3>

Perimeter = 2(length + width)

From given figure in question,

length = 40 feet

width = 80 feet

Therefore,

Perimeter = 2(40 + 80)

Perimeter = 2(120) = 240

Thus, we got,

Perimeter of first parking plot = 240 feet

Also, given that,

$\text{Perimeter of second plot }= \frac{3}{4} \times \text{Perimeter of first parking plot}\\\\\text{Perimeter of second plot }= \frac{3}{4} \times 240\\\\\text{Perimeter of second plot }= 180$

Thus perimeter of second plot is 180 feet

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